a. 301 cg
b. 6.2 km
Explanation:
a. knowing that 1 gram (g) is equal to 100 centigrams (cg) we devise the following reasoning:
if 1 g is equal to 100 cg
then 3.01 g are equal to X cg
X = (3.01 × 100) / 1 = 301 cg
b. knowing that 1 kilometer (km) is equal to 1000 meters (m) we devise the following reasoning:
if 1 km is equal to 1000 m
then Y km are equal to 6200 m
Y = (6200 × 1) / 1000 = 6.2 km
Learn more about:
converting units of measurement
brainly.com/question/11300981
#learnwithBrainly
Answer:
74.81 grams of calcium carbonate are produced from 79.3 g of sodium carbonate.
Explanation:
The balanced reaction is:
Na₂CO₃ + Ca(NO₃)₂ ⟶ CaCO₃ + 2 NaNO₃
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate in the reaction:
- Na₂CO₃: 1 mole
- Ca(NO₃)₂: 1 mole
- CaCO₃: 1 mole
- NaNO₃: 2 mole
Being the molar mass of the compounds:
- Na₂CO₃: 106 g/mole
- Ca(NO₃)₂: 164 g/mole
- CaCO₃: 100 g/mole
- NaNO₃: 85 g/mole
then by stoichiometry the following quantities of mass participate in the reaction:
- Na₂CO₃: 1 mole* 106 g/mole= 106 g
- Ca(NO₃)₂: 1 mole* 164 g/mole= 164 g
- CaCO₃: 1 mole* 100 g/mole= 100 g
- NaNO₃: 2 mole* 85 g/mole= 170 g
You can apply the following rule of three: if by stoichiometry 106 grams of Na₂CO₃ produce 100 grams of CaCO₃, 79.3 grams of Na₂CO₃ produce how much mass of CaCO₃?

mass of CaCO₃= 74.81 grams
<u><em>74.81 grams of calcium carbonate are produced from 79.3 g of sodium carbonate.</em></u>
Electron was discovered by J. J. Thomson in 1897 when he was studying the properties of cathode ray.
a tick attaches itself to the skin of a dog
Explanation:
during this reaction this will produce 2 molecules of No