Answer:
a)
, b)
, c) 
Explanation:
a) The tank can be modelled by the Principle of Mass Conservation:

The mass flow rate exiting the tank is:



b) An expression for the specific enthalpy at outlet is derived from the First Law of Thermodynamics:


Properties of water are obtained from tables:



The specific enthalpy at outlet is:


c) After a quick interpolation from data availables on water tables, the final temperature is:

Efficiency is the minimum use of energy to accomplish the task. The wasted energy will be 375 J when 750 J of energy is given.
<h3>What is wasted energy?</h3>
Wasted energy is energy that is not useful when the transformation in the system occurs.
Total energy = 750 J
The efficiency of the system = 50 %
Output work (OW) is calculated as:
Efficiency = output work ÷ input work × 100%
750 × 50 = 100 OW
OW = 375 J
Wasted energy = Total energy - output work
= 750 - 375
= 375 J
Therefore, the machine is 50 % inefficient and has wasted energy of 375 J.
Learn more about wasted energy here:
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Answer:
COP(heat pump) = 2.66
COP(Theoretical maximum) = 14.65
Explanation:
Given:
Q(h) = 200 KW
W = 75 KW
Temperature (T1) = 293 K
Temperature (T2) = 273 K
Find:
COP(heat pump)
COP(Theoretical maximum)
Computation:
COP(heat pump) = Q(h) / W
COP(heat pump) = 200 / 75
COP(heat pump) = 2.66
COP(Theoretical maximum) = T1 / (T1 - T2)
COP(Theoretical maximum) = 293 / (293 - 273)
COP(Theoretical maximum) = 293 / 20
COP(Theoretical maximum) = 14.65
Answer:
13.95
Explanation:
Given :
Vector A polar coordinates = ( 7, 70° )
Vector B polar coordinates = ( 4, 130° )
To find A . B we will
A ( r , ∅ ) = ( 7, 70 )
A = rcos∅ + rsin∅
therefore ; A = 2.394i + 6.57j
B ( r , ∅ ) = ( 4, 130° )
B = rcos∅ + rsin∅
therefore ; B = -2.57i + 3.06j
Hence ; A .B
( 2.394 i + 6.57j ) . ( -2.57 + 3.06j ) = 13.95
Answer:
Define Variables and Use List methods to do the following
Explanation:
#<em>Conjoins two lists together</em>
all_names = male_names.union(female_names)
#<em>Finds the names that appear in both lists, just returns those</em>
neutral_names = male_names.intersection(female_names)
#<em>Returns names that are NOT in both lists</em>
specific_names = male_names.symmetric_difference(female_names)