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tankabanditka [31]
3 years ago
11

Please help me im going out of my way and giving you extra points I really need some assistance

Chemistry
1 answer:
Hitman42 [59]3 years ago
4 0

Answer:

x=2.8moles

Explanation:

first step balance the chemical equation

C2H6+O2-->CO2+2H2O

use more ratio to find the moles of water

1mole of C2H6= 2 moles of H2O

1.4mole of C2H6=?x

cross multiply

x=2.8 moles of H2O

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10 points<br><br> How many more oxygen atoms are in 3Mg3(PO4)2 than in 4Al2O3?
Feliz [49]

Answer:

12 more oxygen

Explanation:

An atom is the smallest particles that can take part in a chemical reaction

The given compounds are:

        3Mg₃(PO₄)₂  

 Number of oxygen atoms  = 3[2 x 4]  = 24 oxygen atoms

For;

             4Al₂O₃;

   Number of oxygen atoms  = 4 x 3  = 12 oxygen atoms

In   3Mg₃(PO₄)₂  , there are 24  - 12  = 12 more oxygen atoms than in  4Al₂O₃;

6 0
3 years ago
Read 2 more answers
Butane, ch3-ch2-ch2-ch3, is a hydrocarbon fuel used in lighters. how many moles of molecules are there in a 350. gram sample of
Galina-37 [17]
<span>6.03 moles.



1 molecule of butane contains 4 carbon atoms and ten hydrogen atoms.

The molar mass is 4 times the atomic mass of carbon, 12 g/mol, plus 10 times the atomic weight of hydrogen, 1 g/mol.

Molar mass = 4 * 12 g/mol + 10 * 1 g/mol = 58 g/mol.

This means that 1 mole of butane has a mass of 58 g.

To figure out how many moles are in a sample of butane, divide the mass of sample in grams by 58 grams

Number of moles in sample = 350 g / 58 g/mol = 6.03 moles.</span>
3 0
3 years ago
A solution is created by dissolving 11.0 grams of ammonium chloride in enough water to make 235 mL of solution. How many moles o
Amanda [17]

Answer:

The correct answer is 0.206 moles

Explanation:

According to the given scenario, the calculation of the number of moles of ammonium chloride is available in the resulting solution is given below:

Given that

Amount of NH_4Cl is 11.0 grams

And, the volume is 235 mL

Now the molar mass of NH_4Cl is 53.49g/mol

So, the number of moles presented is

= 11.0 ÷ 53.49

= 0.206 moles

hence, the number of moles of ammonium chloride are available in the resulting solution is 0.206 moles

7 0
2 years ago
24. What volume of a 0.0200M calcium hydroxide is required to neutralize 35.00 mL of 0.0500M nitric acid
Natalka [10]

Answer:

THE VOLUME OF 0.200M CALCIUM HYDROXIDE NEEDED TO NEUTRALIZE 35 mL of 0.050 M NITRIC ACID IS 43.75 mL.

Explanation:

Using

Ca VA / Cb Vb = Na / Nb

Ca = 0.0500 M

Va = 35 mL

Cb = 0.0200 M

Vb = unknown

Na = 2

Nb = 1

Equation for the reaction:

Ca(OH)2 + 2HNO3 --------> Ca(NO3)2 + 2H2O

So therefore, we make Vb the subject of the equation and solve for it

Vb = Ca Va Nb / Cb Na

Vb = 0.0500 * 35 * 1 / 0.0200 * 2

Vb = 1.75 / 0.04

Vb = 43.75 mL

The volume of 0.02M calcium hydroxide required to neutralize 35 mL of 0.05 M nitric acid is 43.75 mL

6 0
3 years ago
How many moles of aluminum oxide are produced when 6 moles of oxygen gas react?
siniylev [52]

Answer:

4 moles of aluminum and 6 moles of oxygen are produced

4 0
3 years ago
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