Answer:
A. 6.36 lbm/s
b. 
Explanation:
a. Given the following information;
#Compressor inlet:
Air pressure,
#Compressor outlet:

#Cooling rate,

# From table A-1E
Gas constant of air 
Specific enthalpy at 
Using the mass balance:

Hence, the mass flow rate of the air is 6.36lbm/s
b The specific enthalpy at the exit is defined as the energy balance on the system:

Hence, the temperature at the compressor exit 
I think it would be 77.9 grams
E S *
The "E" represents Earth, "S" represent Sun, and the "*" represents the nearest star(which is Proxima Centauri).
The main thing to worry about here is units, so ill label everything out.
D'e,s'(Distance between earth and sun) = .<span>00001581 light years
D'e,*'(Distance between earth and Proxima) = </span><span>4.243 light years
Now this is where it gets fun, we need to put all the light years into centimeters.(theres alot)
In one light year, there are </span>9.461 * 10^17 centimeters.(the * in this case means multiplication) or 946,100,000,000,000,000 centimeters.
To convert we multiply the light years we found by the big number.
D'e,s'(Distance between earth and sun) = 1.496 * 10^13 centimeters<span>
D'e,*'(Distance between earth and Proxima) = </span><span>4.014 * 10^18 centimeters
</span>
Now we scale things down, we treat 1.496 * 10^13 centimeters as a SINGLE centimeter, because that's the distance between the earth and the sun. So all we have to do is divide (4.014 * 10^18 ) by (<span>1.496 * 10^13 ).
Why? because that how proportions work.
As a result, you get a mere 268335.7 centimeters.
To put that into perspective, that's only about 1.7 miles
A lot of my numbers came from google, so they are estimations and are not perfect, but its hard to be on really large scales.</span>
Answer:
a) 
b) 
Explanation:
From the question we are told that:
Velocity of eagle 
Frequency of eagle 
Velocity of Black bird 
Speed of sound 
a)
Generally the equation for Frequency is mathematically given by



b)
Generally the equation for Frequency is mathematically given by


