Answer:
A block device is a computer data storage device that supports reading and (optionally) writing data in fixed-size blocks, sectors, or clusters. These blocks are generally 512 bytes or a multiple thereof in size
The lowest constant acceleration needed for takeoff from a 1.80 km runway is 2.8 m/s².
To find the answer, we need to know about the Newton's equation of motion.
<h3>What's the Newton's equation of motion to find the acceleration in term of initial velocity, final velocity and distance?</h3>
- The Newton's equation of motion that connects velocity, distance and acceleration is V² - U²= 2aS
- V= final velocity, U= initial velocity, S= distance and a= acceleration
<h3>What's the acceleration, if the initial velocity, final velocity and distance are 0 m/s, 360km/h and 1.8 km respectively?</h3>
- Here, S= 1.8 km or 1800 m, V= 360km/h or 100m/s , U= 0 m/s
- So, 100²-0= 2×a×1800
=> 10000= 3600a
=> a= 10000/3600 = 2.8 m/s²
Thus, we can conclude that the lowest constant acceleration needed for takeoff from a 1.80 km runway is 2.8 m/s².
Learn more about the Newton's equation of motion here:
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It's D. By "net" they mean the overall force the object experiences, so sum all the force vectors, those in a negative direction (eg friction) should be subtracted.
Answer:
The correct answer is - 30 feet.
Explanation:
According to the parking laws one should not park within 30 feet of any flashing signal, stop sign, or traffic signal it is not allowed. Parking is also not allowed in case of the following situations -
On crosswalks
In front of driveways
double parking
On sidewalks.
at "No Parking" signs are posted.
Within intersections or 20 feet of an intersection.
Within 15 feet of a fire hydrant.
So what the thermal energy equation tells you is the internal heat energy a system gives you due to the movement of particles/temperature. This heat is due to the kinetic energy in the particles. Q represents the heat transfer of a material that has a specific mass, m, specific heat, c, and some temperature or change in temperature, ΔT. For example, say you have an object of mass 1kg, specific heat 0.5J/kg°C and the temperature changes from 50°C to 100°C. To find the heat transfer you would use the equation Q= 1kg*0.5J/kg°C*(100°C-50°C). This would tell you that the heat transfer of this particle is 25J which means that 25J of energy are transferred from one point to the other in this system.
