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Fittoniya [83]
2 years ago
12

What is the energy of an electron in a Li+ ion when an electron moves from n = 2 to n =3?

Chemistry
1 answer:
arlik [135]2 years ago
8 0

Answer:

The question wants you to determine the energy that the incoming photon must have in order to allow the electron that absorbs it to jump from

n

i

=

2

to

n

f

=

6

.

A good starting point here will be to calculate the energy of the photon emitted when the electron falls from

n

i

=

6

to

n

f

=

2

by using the Rydberg equation.

1

λ

=

R

⋅

(

1

n

2

f

−

1

n

2

i

)

Here

λ

si the wavelength of the emittted photon

R

is the Rydberg constant, equal to

1.097

⋅

10

7

m

−

1

Plug in your values to find

1

λ

=

1.097

⋅

10

7

.

m

−

1

⋅

(

1

2

2

−

1

6

2

)

1

λ

=

2.4378

⋅

10

6

.

m

−

1

This means that you have

λ

=

4.10

⋅

10

−

7

.

m

So, you know that when an electron falls from

n

i

=

6

to

n

f

=

2

, a photon of wavelength

410 nm

is emitted. This implies that in order for the electron to jump from

n

i

=

2

to

n

f

=

6

, it must absorb a photon of the same wavelength.

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<span>C4H10 + 6.5 O2 ----> 4CO2 + 5H2O 

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4. Now multiply everything on the equation by two so you have nice integer numbers. 

5. check you have the same amount of everything on each side. 
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6 0
3 years ago
In fractional distillation, liquid can be seen running from the bottom of the distillation column back into the distilling flask
shepuryov [24]

Answer:

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Explanation:

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7 0
3 years ago
What can occur in physical change ?
Alexandra [31]

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Hope this helped

5 0
3 years ago
If the half-life of a radioactive element is 4 days, how long will it take for three- fourths of a sample of the element to deca
Jlenok [28]

Answer:

\boxed{\text{8 da}}

Explanation:

The question will be easier to solve if we interpret it as, " How long will it take until one-fourth of a sample of the element remains,?"

The half-life of the element is the time it takes for half of it to decay.  

After one half-life, half (50 %) of the original amount will remain.  

After a second half-life, half of that amount (25 %) will remain, and so on.  

We can construct a table as follows:

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\text{We see that 8 da is two half-lives, and the fraction of the element remaining is $\frac{1}{4}$.}\\\text{It takes $\boxed{\textbf{8 da}}$ for three-fourths of the element to decay}

3 0
3 years ago
When chromium loses two electrons, its configuration changes to
damaskus [11]

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So its electronic configuration becomes,  

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So the answer here is D. [Ar]3d⁴ -because after losing 2 electrons electronic configuration of cromium becomes  [Ar] 3d⁴.


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