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Anna [14]
3 years ago
6

Chemical A breaks down into chemical B. At t=0, [A] = 0.100 M. At t=10.0 s, [A] = 0.075 M. What is the average reaction rate?

Chemistry
1 answer:
RoseWind [281]3 years ago
6 0

Answer:

a0.0075 mi i think so ok but average is need to add and divide

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When is di- used in the name of a hydrocarbon?
harkovskaia [24]
Di- is used when you are naming organic compounds. If you have the same substituent repeated twice in the compund
For example: CH3-CH(CH3)-CH2-CH(CH3)-CH3
This will be named 2,4-dimethylpentane
6 0
3 years ago
The 225 g FeCl2 is about 1.8 moles.
Lyrx [107]

Answer:

4 \frac{mol}{l}

Explanation:

From the question, we have been asked to find the molarity of FeCl2 having a volume of 450 mL,

We have been provided with 225 g which is proportional to 1.8 moles.

We know that molarity of any solution should be in mol/L.

1 mole contained in 1 L means it has a molarity of 1 mol/L

Let's convert 450 mL to Litres which is,

\frac{450}{1000} litres

= 0.450 L

Thus,

1 mole is contained in 1L

x moles are contained in 0.450 L

Hence,

x mole/molarity = {1 mole x 1 L}/{0.450 L}

= 4 mol/L

Therefore 4 mol/L is the molar concentration.

5 0
2 years ago
The following reaction does not proceed to a product: H2O + Cu --> no reaction. Why is that?
Anettt [7]
I think the correct answer would be because copper has a lower activity than hydrogen and cannot replace the bonds in it. Substances that are not oxidizing do not react with copper since the redox potentials are very low. Hope this answers the question.
5 0
4 years ago
Read 2 more answers
In which of the following compounds does the carbonyl stretch in the IR spectrum occur at the lowest wavenumber?
klio [65]

Answer:

a. Cyclohexanone

Explanation:

The principle of IR technique is based on the <u>vibration of the bonds</u> by using the energy that is in this region of the electromagnetic spectrum. For each bond, there is <em>a specific energy that generates a specific vibration</em>. In this case, you want to study the vibration that is given in the carbonyl group C=O. Which is located around 1700 cm-1.

Now, we must remember that the <u>lower the wavenumber we will have less energy</u>. So, what we should look for in these molecules, is a carbonyl group in which less energy is needed to vibrate since we look for the molecule with a smaller wavenumber.

If we look at the structure of all the molecules we will find that in the last three we have <u>heteroatoms</u> (atoms different to carbon I hydrogen) on the right side of the carbonyl group. These atoms allow the production of <u>resonance structures</u> which makes the molecule more stable. If the molecule is more stable we will need more energy to make it vibrate and therefore greater wavenumbers.

The molecule that fulfills this condition is the <u>cyclohexanone.</u>

See figure 1

I hope it helps!

4 0
3 years ago
A good way to organize and record your results and observations is
Zielflug [23.3K]
It is a graph. It shows observations and then you record your results with any of the graph types.
5 0
3 years ago
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