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MrRissso [65]
3 years ago
7

How many miles must you travel to make the Earth fall the same amount?

Physics
1 answer:
Ede4ka [16]3 years ago
4 0

Let's take the analogy of the baseball pitcher a step farther. When a baseball is thrown in a straight line, we already said that the ball would fall to Earth because of gravity and atmospheric drag. Let's pretend again that there is no atmosphere, so there is no drag to slow the baseball down. Now, let's assume that the person throwing the ball throws it so fast that as the ball falls towards the Earth, it also travels so far, before falling even a little, that the Earth's surface curves away from the ball's path.

In other words, the baseball falls as it did before, but the ball is moving so fast that the curvature of the Earth becomes a factor and the Earth "falls away" from the ball. So, theoretically, if a pitcher on a 100 foot (30.48 m) high hill threw a ball straight and fast enough,the ball would circle the Earth at exactly 100 feet and hit the pitcher in the back of the head once it circled the globe! The bad news for the person throwing the ball is that the ball will be traveling at the same speed as when they threw it, which is about 8 km/s or several times faster than a rifle bullet. This would be very bad news if it came back and hit the pitcher, but we'll get to that in a minute.

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If 2.2 lbs = 1.0 kg, and Megan Progress weighs 130 lbs, what is her weight in newtons?
Dafna11 [192]

Answer:

Force = 2802.8 Newton

Explanation:

Given the following data;

Mass = 130 lbs

But, 2.2 lbs = 1.0 kg

130 lbs to kg = 130 * 2.2 = 286 kg

Acceleration due to gravity = 9.8m/s²

To find the force in Newton;

Force = mass * acceleration due to gravity

Force = 286 * 9.8

Force = 2802.8 Newton

8 0
3 years ago
An object of mass m is traveling around a circle of radius v. What happens to the centripetal force if the radius is cut in half
german

Answer:

Centripetal force doubles

Explanation:

Since centripetal force is given by

F=\frac {mv^{2}}{r}

Where F is the centripetal force, m is the mass, v is the centripetal velocity and r is circle radius.

When the radius is reduced to half then the centripetal force will be

F=\frac {mv^{2}}{0.5r}=\frac {2mv^{2}}{r}

Evidently, the centripetal force is doubled compared to the initial.

Note that while the question gives letter v for radius, I used v for velocity and r for radius since these are the standard letters for abbreviating formula of centripetal force.

7 0
3 years ago
According to coulombs law, how is the electric force related to the distance between two charges?
lorasvet [3.4K]

Answer:

D

Explanation:

From the formula of coulombs law F = Kq1q2/square of r, we can say the electric force is indirectly related to square of r

4 0
3 years ago
A speed bike tops a hill at 3.50 m/s and accelerates steadily down the hill until reaching a speed of 11.4 m/s after 4.20 second
k0ka [10]

Answer:

The bike traveled 31.3 meters during this period

Explanation:

A speed bike tops a hill at 3.50 m/s and accelerates steadily down the

hill until reaching a speed of 11.4 m/s after 4.20 seconds

→ The initial speed u = 3.5 m/s

→ The final speed v = 11.4 m/s

→ The time of acceleration t = 4.2 seconds

→ a = \frac{v-u}{t}

Substitute the values above in the rule to find the acceleration a

→ a = \frac{11.4-3.5}{4.2} = 1.88 m/s²

We need to find the distance that the bike traveled during the

acceleration

→ v² = u² + 2 a s, where s is the distance

→ (11.4)² = (3.5)² + 2 (1.88)(s)

→ 129.96 = 12.25 + 3.76 s

Subtract 12.25 from both sides

→ 117.71 = 3.76 s

Divide both sides by 3.76

→ s = 31.3 meters

<em>The bike traveled 31.3 meters during this period</em>

8 0
3 years ago
A bullet with mass 0.04000 kg, traveling at a speed of 310.0 m/s, strikes a stationary block of wood having mass 6.960 kg. The b
ch4aika [34]

Answer:

1.77 m/s

Explanation:

From the law of conservation of momentum,

Total momentum before collision = Total momentum after collision

mu+m'u' = V(m+m')............................ Equation 1

Where m = mass of the bullet, m' = mass of the block, u = initial velocity of the bullet, u' = initial velocity of the block, V = Velocity of the bullet-wood combination immediately after collision

make V the subject of the equation

V = (mu+m'u')/(m+m').................. Equation 2

Given: m = 0.04 kg, m' = 6.96 kg, u = 310 m/s, u' = 0 m/s (stationary)

Substitute into equation 2

V = (0.04×310+6.96×0)/(0.04+6.96)

V = 12.4/7

V = 1.77 m/s

Hence the speed, in m/s, of the bullet-plus-wood combination immediately after the collision is 1.77 m/s

6 0
3 years ago
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