All categories

2 years ago

If two 1000kg cars have a gravitational force of 1.067x10^-5 N towards each other, how far apart are they?

Physics

1 answer:

Taya2010 [7]2 years ago

4 0

Answer:

6.25m

Explanation:

Given parameters:

Masses of the car = 1000kg

Gravitational force = 1.067 x 10⁻⁵N

Unknown:

Distance between them = ?

Solution:

To solve this problem, we use the expression below from the universal gravitational law;

Fg = $\frac{G x mass 1 x mass 2}{distance^{2} }$

G = 6.67 x 10⁻¹¹

1.067 x 10⁻⁵ = $\frac{6.67 x 10^{-11} x 1000 x 1000 }{d^{2} }$

d = 6.25m

You might be interested in

What are the 26th - 50th Elements of the Periodic Table

Jet001 [13]

The 26th is Fe(iron) and the 50th is Sn(tin)

3 0

3 years ago

Sam is moving house and is carrying a 300N box of books up a flight of steps 5m high, it takes her 30 seconds. Gary follows her

ioda

Answer: Sam provides the biggest power

Explanation: <u>Power</u> is defined, in Physics, as the rate of work done. <u>Work</u> is energy transferred to an object due to the force causing the displacement of the object.

So, to determine Power:

For Sam:

P = $\frac{work}{time}$

$P=\frac{F.d}{t}$

$P=\frac{300.5}{30}$

P = 50 Watts

The unit for Power is [P] = J/s = Watt

For Gary:

P = $\frac{work}{time}$

$P=\frac{1000}{25}$

P = 40 Watts

Comparing power of Sam and Gary, we can conclude that Sam provides the biggest power of 50 Watts.

7 0

2 years ago

An airplane is trying to fly at a speed of 300 miles per hour straight North, but a 70 miles per hour wind is blowing toward the

OlgaM077 [116]

Answer:

V = 308.06 miles/hour

θ = 13.13° west of north.

Explanation:

Airplane speed = V₁ = 300 miles/hour

Wind speed = V₂ = 70 miles/hour

Resultant speed of the plane = V = ?

As airplane is trying to fly straight North and wind is blowing toward the west. So the angle between airplane velocity and wind velocity is 90°.

By Pythagoras Theorem

V = $\sqrt{V_{1}^{2}+V_{2}^{2} }$

V = $\sqrt{300^{2}+70^{2} }$

V = 308.06 miles/hour

θ = tan⁻¹(70/300)

θ = 13.13° west of north.

3 0

2 years ago

The Explorer VIII satellite, placed into orbit November 3, 1960, to investigate the ionosphere, had the following orbit paramete

PIT_PIT [208]

Answer:

$\frac{v_p}{v_a}=1.268$

Explanation:

1) Basic concepts

Apogee: is the maximum distance for an object orbiting the Earth. For this case the distance for the apogee would be the sum of radius for the earth and 2289 km.

Perigee: Minimum distance of an object orbiting the Earth. For this case the distance for the perigee would be the sum of radius for the earth and 459 km.

A good approximation for these terms are related to the figure atached.

Isolated system: That happens when the system is not subdued to an external torque, on this case the change of angular momentum would be 0.

2) Notation and data

$r_{earth}$ radius for the Earth, looking for this value on a book we got $r_{earth}=6.37x10^{3}km$

$r_p =459km +r_{earth}=459km +6.37x10^3 km=6.829x10^3 km$ , represent the radius for perigee

$r_a =2289km +r_{earth}=2289km +6.37x10^3 km=8.659x10^3 km$ , represent the radius for perigee

$T=112.7min$ , period

$v_p$ velocity of the perigee

$v_p$ velocity of the apogee

$r=\frac{v_p}{v_a}$ is the variable of interest represented the ratio for the speed of the perigee to the speed of the apogee

3) Formulas to use

We don't have torque from the gravitational force since is a centered force. So the change of momentum is 0

$\Delta L=0$ (1)

$L_a=L_p$ (2)

From the definition of angular momentum we have $L_i=mv_i r_i$ , replacing this into equation (2) we got:

$mv_a r_a =mv_p r_p$ (3)

We can cancel the mass on both sides

$v_a r_a =v_p r_p$ (4)

And solving $\frac{v_p}{v_a}$ we got:

$\frac{v_p}{v_a}=\frac{r_a}{r_p}$ (5)

And replacing the values obtained into equation (5) we got:

$\frac{v_p}{v_a}=\frac{8.659x10^3 km}{6.829x10^3 km}=1.268$

And this would be the final answer $\frac{v_p}{v_a}=1.268$

8 0

2 years ago

Describe why we fear flying in a plane, nuclear power plants, being struck by lightning, or exposure to BPA in plastics MORE tha

Phantasy [73]

Answer:

Flying in a plane gives the notion of one exiting the earths atmosphere and also, there is the risk of exposure to dangerous cosmic radiation.

Nuclear power plants possesses great forms of chemicals and toxic elements that could lead to chemical radiation and further more, cause mutation of human cells which invariably brings cancer. There is the extreme health hazard to be weary of when in a nuclear power plant.

Being struck by lightning can be hazardous to ones health and could bring forth a number of health problems like; hearing and/or vision loss, irregular heartbeat, headache, chest pain, hypersomnia, confusion, shortness of breath, weakness, stiffness, and/or temporary paralysis.

Exposure to BPA in plastics has been connected to be cause of a number of fertility problems, male impotence, heart disease, and other conditions.

What do all of these problems have in common? They all are things you never see coming, you can't literally control the particles from nuclear plants, the forces handling the elevation and descending of planes, the chemical and physical nature of compounds involved in lightning production as compared to not exercising and knowing what could come from that. The side effects of not exercising can not be compared to the latter explained and those are life threatening processes.

3 0

2 years ago