Answer:
a. Heat Capacity = 1.756J/mol-K
b. Heat Capacity = 24.942J/mol-k
Explanation:
Given
Constant volume Cv = 0.81J/mol-k
T1 = 34K
Td = Debye temperature = 306 K. Estimate the heat capacity (in J/mol-K) a. 44 K
First, The value of the temperature-independent constant.
Using Cv = AT³
Make A the subject of formula
A = Cv/T³
Substitute each values
A = 0.81/34³
A = 0.000020608589456543
A = 2.061 * 10^-5J/mol-k
The heat capacity changes with the temperature; below is the relationship between heat capacity and the temperature
Cv = AT³
So, The heat capacity when T = 44k is then calculated as
Cv = 2.061 * 10^-5 * 44³
Cv = 1.755522084266232
Cv = 1.756J/mol-K
(b) at 477 K.
Because the temperature is larger than the Debye temperature, the specific heat is calculated using as:
Cv = 3R
Where R = universal gas constant
R = 8.314J/mol-k
Cv = 3 * 8.314
Cv = 24.942J/mol-k
Answer:
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Answer:
D. 539,000 J
Explanation:
The formula for potential energy(P.E) =mgh where m is mass of object, g is gravity acceleration 9.8 m/s² and h is height in meters.
From the question ;
m=500 kg
g= 9.8 m/s²
h= 110 m
P.E = mgh
= 500*9.8*110
=539,000 J
Answer option D
The other options are incorrect because the calculated values for the potential energy of the train are not equal to 539,000 J.
This question involves the concepts of power and current.
The power output of the motor is "10.08 hp".
<h3>Power Output</h3>
The power output of the motor can be found using the following formula:
P = ηVI
where,
- P = Power = ?
- η = efficiency = 90 % = 0.9
- I = current = 38 A
- V = potential difference = 220 V
Therefore,
P = (0.9)(38 A)(220 V)
P = 7524 watt
converting this to horsepower:
P = (7524 watt)()
P = 10.08 hp
Learn more about power here:
brainly.com/question/13948282
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Answer:
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