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3 years ago

You filled a balloon that has a volume of 45 cm3 with helium gas. What is the volume of the helium gas?

Engineering

1 answer:

dangina [55]3 years ago

6 0

Answer:

The volume of the helium gas is 45 cm³.

Explanation:

The volume of the helium gas can be determined from kinetic theory of gases, which states that gas molecules do not have a fixed volume, rather they assume the volume of their container.

Therefore, if the volume of the balloon is 45 cm³, which is also the container of the helium gas, then the volume of the helium gas is 45 cm³.

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4.10.1: Simon says. "Simon Says" is a memory game where "Simon" outputs a sequence of 10 characters (R, G, B, Y) and the user mu

AleksandrR [38]

Answer:

for i in range(0,10):

if SimonPattern[i] == UserPattern[i]:

score = score + 1

i = i + 1

else:

break

if i == 9:

score = score + 1

print("Total Score: {}".format(score))

Explanation:

This for loop was made using Python. Full code attached.

For loop requires a range of numbers to define the end points. For this Simon Says game, we are talking about 10 characters, so that must be the range for the for loop: from 0 to 10.
Conditional if tests if Simon pattern matches User's one characheter by one and add point for each match.
Break statement is ready to escape the for loop at first mismatch.
As we are starting from index 0, if the users matched all the characters correctly, then we need to add 1, otherwise the maximun score would be 9 and it should be 10.

Download txt

5 0

3 years ago

About what thickness of aluminum is needed to stop a beam of (a) 2.5-MeV electrons, (b) 2.5-MeV protons, and (c) 10-MeV alpha pa

Nana76 [90]

The thickness of aluminium needed to stop the beam electrons, protons and alpha particles at the given dfferent kinetic energies is 1.5 x 10⁻¹⁴ m.

<h3>Thickness of the aluminum</h3>

The thickness of the aluminum can be determined using from distance of closest approach of the particle.

$K.E = \frac{2KZe^2}{r}$

where;

Z is the atomic number of aluminium = 13
e is charge
r is distance of closest approach = thickness of aluminium
k is Coulomb's constant = 9 x 10⁹ Nm²/C²

<h3>For 2.5 MeV electrons</h3>

$r = \frac{2KZe^2}{K.E} \\\\r = \frac{2 \times 9\times 10^9 \times 13\times (1.6\times 10^{-19})^2}{2.5 \times 10^6 \times 1.6 \times 10^{-19}} \\\\r = 1.5 \times 10^{-14} \ m$

<h3>For 2.5 MeV protons</h3>

Since the magnitude of charge of electron and proton is the same, at equal kinetic energy, the thickness will be same. r = 1.5 x 10⁻¹⁴ m.

<h3>For 10 MeV alpha-particles</h3>

Charge of alpah particle = 2e

$r = \frac{2KZe^2}{K.E} \\\\r = \frac{2 \times 9\times 10^9 \times 13\times (2 \times 1.6\times 10^{-19})^2}{10 \times 10^6 \times 1.6 \times 10^{-19}} \\\\r = 1.5 \times 10^{-14} \ m$

Thus, the thickness of aluminium needed to stop the beam electrons, protons and alpha particles at the given dfferent kinetic energies is 1.5 x 10⁻¹⁴ m.

Learn more about closest distance of approach here: brainly.com/question/6426420

7 0

2 years ago

‼️Will mark brainliest‼️

Slav-nsk [51]

YAll don’t tell my cousin I’m hacking her school resources because I got a 0 in a test and she got a 100

4 0

2 years ago

Need help with both giving out brainlest for the people to help me

sammy [17]

The first one is d or the 4th answer choice and the second one is false. Hope this helps!

4 0

2 years ago

Suppose the working pressure for a boiler is 10 psig, then what is the corresponding absolute pressure?

yanalaym [24]

Answer:

The corresponding absolute pressure of the boiler is 24.696 pounds per square inch.

Explanation:

From Fluid Mechanics, we remember that absolute pressure ( $p_{abs}$ ), measured in pounds per square inch, is the sum of the atmospheric pressure and the working pressure (gauge pressure). That is: