Question

Help will give brainliest!!

Answer 1

Half reaction :

Oxidation

Cu ⇒ Cu²⁺ + 2e⁻

Reduction

2Ag⁺+ 2e⁻ ⇒2Ag  

Further explanation

Given

Reaction

Cu+2AgNO₃⇒Cu(NO₃)₂+2Ag

Required

Oxidation and reduction half-reactions

Solution

Oxidation is an increase in oxidation number, while reduction is a decrease in oxidation number.

• Oxidation

Cu ⇒ Cu²⁺ + 2e⁻

0 to +2

• Reduction

2Ag⁺+ 2e⁻ ⇒2Ag  

+1 to 0