Answer:
∆H = negative and ∆S = positive.
Explanation:
The reaction given in the question is spontaneous at room temperature ,
hence ,
The the gibbs free energy , i.e. ,∆G will be negative for spontaneous reaction
According to the formula ,
∆G = ∆H -T∆S
The value of ∆G can be negative , if ∆H has a negative value and ∆S has a positive value , because , T∆S , has a negative sign .
Hence , the answer will be , ∆H = negative and ∆S = positive.
Answer:
C₂H₂ + 3H₂ ⟶ 2CH₄
Explanation:
The initial concentrations are:
[CH₄] = 6.30 ÷ 6.00 = 1.05 mol·L⁻¹
[C₂H₂] = 4.20 ÷ 6.00 = 0.700 mol·L⁻¹
[H₂] = 11.15 ÷ 6.00 = 1.858 mol·L⁻¹
2CH₄ ⇌ C₂H₂ + 3H₂
I/mol·L⁻¹: 1.05 0.700 1.858
![Q = \dfrac{\text{[C$_{2}$H$_{2}$][H$_{2}$]}^{3}}{\text{[CH$_{4}$]}^{2}} = \dfrac{ 0.700\times 1.858^{3}}{1.05^{2}}= 4.07](https://tex.z-dn.net/?f=Q%20%3D%20%5Cdfrac%7B%5Ctext%7B%5BC%24_%7B2%7D%24H%24_%7B2%7D%24%5D%5BH%24_%7B2%7D%24%5D%7D%5E%7B3%7D%7D%7B%5Ctext%7B%5BCH%24_%7B4%7D%24%5D%7D%5E%7B2%7D%7D%20%3D%20%5Cdfrac%7B%200.700%5Ctimes%201.858%5E%7B3%7D%7D%7B1.05%5E%7B2%7D%7D%3D%204.07)
Q > K
That means we have too many products.
The reaction will go to the left to get rid of the excess products.
C₂H₂ + 3H₂ ⟶ 2CH₄
<span>Answer:
1170 ml is the final volume of the sample of gas, if the pressure and moles in the container is kept constant.</span>
Answer to Diethyl ether can<span> be made from </span>ethanol<span>. The </span>reaction<span> is 2C2H5OH(</span>l) ----> (C2H5)2 O(l<span>) + </span>H2O(l<span>) The </span>percent yield<span> of diet...</span>
