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nirvana33 [79]
2 years ago
7

Any Number that is divisible by four is also divisible by eight

Mathematics
1 answer:
Tomtit [17]2 years ago
4 0

Answer:

The answer is 16 .

Step-by-step explanation:

Hope you got it

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Troy’s canoe is 18 feet long. Ariel’s canoe is 5\6 the length of Troy’s canoe.
sukhopar [10]
5/6 = .83333333333333333333333333.... It goes on...
.833333333333333333 * 18 = 15 
15 is your answer

Another way you could do it is 18/6 = 3
3+3+3+3+3 = 15 

3 being 1/6th of 18  *Hope This Helps...*
6 0
3 years ago
-8)(56)=1<br><br> What is the missing value that makes the equation true?
Rudik [331]
the correct answer is -448
7 0
3 years ago
Find the axis of symmetry and vertex of the following y= -2x2-3x+2
Mnenie [13.5K]
Y= -2x²-3x+2, (form y = ax² +b .x + c

The parabola opens downward & hence it's Vertex is a MAXIMUM.

We know that the axis of symmetry is -b/2a ==>3/(-4) ==>
x= - 3/4 (axis of symmetry. At x=-3/4 , y = 25/8 = 3.125

Hence the axis of symmetry is x= - 3/4 & the vertex is at (-3/4, 25/8)
8 0
3 years ago
I will mark you brainiest if you can answer this
Katarina [22]

Answer:

C

Step-by-step explanation:

Gl :>

4 0
2 years ago
Suppose that when a transistor of a certain type is subjected to an accelerated life test, the lifetime x (in weeks) has a gamma
elena-14-01-66 [18.8K]

Answer:

a) P(1 \leq X \leq 40)

In order to find this probability we can use excel with the following code:

=GAMMA.DIST(40;5,8,TRUE)-GAMMA.DIST(1,5,8,TRUE)

And we got:

P(1 \leq X \leq 40)=0.560

b) P(X \geq 40)=1-P(X

In order to find this probability we can use excel with the following code:

=1-GAMMA.DIST(40,5,8,TRUE)

And we got:

P(X \geq 40)=1-P(X

Step-by-step explanation:

Previous concepts

The Gamma distribution "is a continuous, positive-only, unimodal distribution that encodes the time required for \alpha events to occur in a Poisson process with mean arrival time of \beta"

Solution to the problem

Let X the random variable that represent the lifetime for transistors

For this case we have the mean and the variance given. And we have defined the mean and variance like this:

\mu = 40 = \alpha \beta  (1)

\sigma^2 =320= \alpha \beta^2  (2)

From this we can solve \alpha and [/tex]\beta[/tex]

From the condition (1) we can solve for \alpha and we got:

\alpha= \frac{40}{\beta}    (3)

And if we replace condition (3) into (2) we got:

320= \frac{40}{\beta} \beta^2 = 40 \beta

And solving for \beta = 8

And now we can use condition (3) to find \alpha

\alpha=\frac{40}{8}=5

So then we have the parameters for the Gamma distribution. On this case X \sim Gamma (\alpha= 5, \beta=8)

Part a

For this case we want this probability:

P(1 \leq X \leq 40)

In order to find this probability we can use excel with the following code:

=GAMMA.DIST(40;5,8,TRUE)-GAMMA.DIST(1,5,8,TRUE)

And we got:

P(1 \leq X \leq 40)=0.560

Part b

For this case we want this probability:

P(X \geq 40)=1-P(X

In order to find this probability we can use excel with the following code:

=1-GAMMA.DIST(40,5,8,TRUE)

And we got:

P(X \geq 40)=1-P(X

6 0
3 years ago
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