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Fed [463]
3 years ago
8

Lexington walked to her friends house.lexie walked 2miles west then 5 miles south then 3 miles east then 4 miles north then 2 mi

les east and finally 1 mile north what is levies distance and displacement.​
Physics
1 answer:
vampirchik [111]3 years ago
4 0
The answer is 17 for the miles
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A temperature of a 50 kg block increases by 15°C when 337,500 J thermal energy are added to the block. what is the block made of
DENIUS [597]

Answer:

Iron

Explanation:

H = mc∅

Above equation can be used here to find the answer to the question. this equation gives us the relationship between the heat energy supplied to a material and the temperature difference that the material would go through according to its mass.

here H is the Heat energy supplied to the material. m is the mass of the material. c is the specific heat capacity of the material and ∅ is the temperature difference applied to the material. we are given that H= 337,500J , m = 50 kg and ∅ = 15 °C. so from the equation now we can calculate the value of c. after calculating c we can find the material because c is an unique value for a particular material. no two materials have the same c value.

c = 337500/(50*15)

c = 450 J/(kg°C) - Iron (google the heat capacity value to find the answer Iron)

8 0
3 years ago
Using Kepler's 3rd law and Newton's law of universal gravitation, find the period of revolution P of the planet as it moves arou
weeeeeb [17]

Answer:

P =  \pi \sqrt{\frac{(R_1+R_2)^3}{2 \ GMS}}

Explanation:

From the attached diagram below:

AC = a (1 + e) = R₂     -------- equation (1)

CD = a ( 1 - e) = R₁     ---------   equation (2)

⇒ 1 - e = \frac{R_1}{a}

e= 1 - \frac{R_1}{a}

Replacing the value for e into equation (1)

a(1+1- \frac{R_1}{a})= R_2

= 2a - R_1 = R_2

a= \frac{R_1+R_2}{2}

From Kepler's third law;

P = 2 \pi \sqrt{\frac{a^3}{GMS}}

P = 2 \pi \sqrt{\frac{(R_1+R_2)^3}{8GMS}}

P =  \pi \sqrt{\frac{(R_1+R_2)^3}{2 \ GMS}}

5 0
3 years ago
A car travels 150 kilometers west in 3 hours. What is its average velocity?
Natalka [10]

Answer:

50 km/hr

Explanation:

150 km devided into 3 hours is 50

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3 years ago
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I would recommend using plastic or steel tweezers.
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Which describes farsightedness? O Distant objects are blurry. O Concave lenses can correct it. O Objects appear larger when wear
Nostrana [21]

Answer:

<em><u> O Distant objects are blurry. </u></em><em> </em><em>describes farsightedness</em><em>.</em>

Explanation:

<em><u>Farsightedness (hyperopia) is a common vision condition in which you can see distant objects clearly, but objects nearby may be blurry. The degree of your farsightedness influences your focusing ability</u></em><em><u>.</u></em><em><u>Farsightedness (hyperopia) is a common vision condition in which you can see distant objects clearly, but objects nearby may be blurry.</u></em>

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2 years ago
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