Question

15 points!

Answer 1

Answer:

$4.12\times 10^{-5}\ J$.

Explanation:

Given that,

Capacitance, $C=1.4\times 10^{-7}\ F$

Charge stored in the capacitor, $Q=3.4\times 10^{-6}\ C$

We need to find the electric potential energy stored in the capacitor. The formula for the electric potential energy stored in the capacitor is given by :

$E=\dfrac{Q^2}{2C}$

Put all the values,

$E=\dfrac{(3.4\times 10^{-6})^2}{2\times 1.4\times 10^{-7}}\\\\=4.12\times 10^{-5}\ J$

So, the required electric potential eenergy is equal to $4.12\times 10^{-5}\ J$.