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sergey [27]
2 years ago
9

Is 11/20 greater than 40% ?

Mathematics
2 answers:
erica [24]2 years ago
7 0

Answer:

The answer is yes

Step-by-step explanation:

expeople1 [14]2 years ago
5 0

Answer:

No

Step-by-step explanation:

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The proof that ΔACB ≅ ΔECD is shown. Given: AE and DB bisect each other at C. Prove: ΔACB ≅ ΔECD What is the missing statement i
GarryVolchara [31]

Answer:

The missing statement is ∠ACB ≅ ∠ECD

Step-by-step explanation:

Given two lines segment AC and BD bisect each other at C.

We have to prove that ΔACB ≅ ΔECD

In triangle ACB and ECD

AC=CE    (Given)

BC=CD   (Given)

Now to prove above two triangles congruent we need one more side or angle

so, as seen in options the angle ∠ACB ≅ ∠ECD due to vertically opposite angles

hence, the missing statement is ∠ACB ≅ ∠ECD


9 0
2 years ago
Read 2 more answers
What is 46785392+78 ?
worty [1.4K]
The answer is 46,785,470
7 0
2 years ago
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Help ASAp peaseeeeeeeeee
PIT_PIT [208]

Answer:

7/6

Step-by-step explanation:

\frac{ \frac{x}{4}  +  \frac{x}{3} }{ \frac{x}{2} }  = \frac{x( \frac{1}{4}  +  \frac{1}{3} )}{ x(\frac{1}{2}) } \\  =  \frac{ \frac{1}{4}  +  \frac{1}{3} }{ \frac{1}{2} }  \\  =  \frac{14}{12}  =  \frac{7}{6}

3 0
2 years ago
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Does anyone know how to solve this? It’s really starting to stress me out.
bekas [8.4K]

Answer:

π − 12

Step-by-step explanation:

lim(x→2) (sin(πx) + 8 − x³) / (x − 2)

If we substitute x = u + 2:

lim(u→0) (sin(π(u + 2)) + 8 − (u + 2)³) / ((u + 2) − 2)

lim(u→0) (sin(πu + 2π) + 8 − (u + 2)³) / u

Distribute the cube:

lim(u→0) (sin(πu + 2π) + 8 − (u³ + 6u² + 12u + 8)) / u

lim(u→0) (sin(πu + 2π) + 8 − u³ − 6u² − 12u − 8) / u

lim(u→0) (sin(πu + 2π) − u³ − 6u² − 12u) / u

Using angle sum formula:

lim(u→0) (sin(πu) cos(2π) + sin(2π) cos(πu) − u³ − 6u² − 12u) / u

lim(u→0) (sin(πu) − u³ − 6u² − 12u) / u

Divide:

lim(u→0) [ (sin(πu) / u) − u² − 6u − 12 ]

lim(u→0) (sin(πu) / u) + lim(u→0) (-u² − 6u − 12)

lim(u→0) (sin(πu) / u) − 12

Multiply and divide by π.

lim(u→0) (π sin(πu) / (πu)) − 12

π lim(u→0) (sin(πu) / (πu)) − 12

Use special identity, lim(x→0) ((sin x) / x ) = 1.

π (1) − 12

π − 12

3 0
3 years ago
Work out the height of a parallelogram with a base of 10m and an area of 60m2
noname [10]
Area formula of a parallelogram is
        A = base x height

Given are the
Area = 60 m² and base = 10 m

 Substitute the given:

60 = 10h  (divide by 10 to find value of h)
\frac{60}{10} = \frac{10h}{10}  (10 and 10 cancels out)

h = 6
The height of a parallelogram with a base of 10m and an area of 60m² is 6m

3 0
3 years ago
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