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rewona [7]
3 years ago
15

The Chalfont soils are a distinct group of soils found in Pennsylvania, New Jersey, and Maryland. The parent material for these

soils is made of silt-sized particles. These particles were originally deposited by glaciers and then later eroded and redeposited in their current location by the wind.
Which of the following terms best describes the Chalfont soils' parent material?
A.
topsoil
B.
humus
C.
loam
D.
loess
Chemistry
2 answers:
4vir4ik [10]3 years ago
8 0

Answer:

D. loess

Explanation:

Loess is a type of fertile soil formed from the action of winds that allows the accumulation of fine and very small grains (between 20 and 50 micrometres) of clay, calcium, feldspar, quartz and other minerals. This type of soil is found mainly in regions of humid or humid climate, with mild relief and significant presence of winds. About 10% of the soil on planet Earth is Loess type or similar, however, this type of soil is found in Pennsylvania, New Jersey, and Maryland.

Lelechka [254]3 years ago
7 0
I believe the answer is D. loess. The loess soil is a predominantly silt-sized sediment formed by accumulation of wind blown dust. This soil is highly porous, homogeneous, pale yellow and friable. One way of forming loess is from glaciers and that is why they contain glacially ground flour like clay and silt.
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Have you had the chance to watch a tree grow over a span of several years? Did you notice that the tree grew thicker and taller?
Kruka [31]

Explanation:

All of the cells would be identical.

is correct answer

3 0
2 years ago
The following question appears on a quiz: ""You fill a tank with gas at 60°C to 100 kPa and seal it. You decrease the temperatu
dusya [7]

Answer: The final pressure will decrease ad the value is 85 kPa

Explanation:

To calculate the final pressure of the system, we use the equation given by Gay-Lussac Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{P_1}{T_1}=\frac{P_2}{T_2}

where,

P_1\text{ and }T_1 are the initial pressure and temperature of the gas.

P_2\text{ and }T_2 are the final pressure and temperature of the gas.

We are given:

P_1=100kPa\\T_1=60^0C=(60+273)K=333K\\P_2=?\\T_2=10^0C=(10+273)K=283K

Putting values in above equation, we get:

\frac{100kPa}{333K}=\frac{P_2}{283K}\\\\P_2=85kPa

Hence, the final pressure will decrease ad the value is 85 kPa

8 0
3 years ago
_________ is a systematic method of naming chemical compounds. This creates an unambiguous and consistent name for any chemical
Vlada [557]

Answer: IUPAC NOMENCLATURE

Explanation:

IUPAC stands for International Union of Pure and Applied Chemistry. They devised a systematic method for naming compounds in order to create a uniform global unambiguous system of nomenclature hence making it easier for researchers to share information more freely without the hindrance of reporting the same compound using different names in different parts of the world thus creating confusion in chemical literature.

6 0
3 years ago
What are examples of everyday chemical reactions?
Softa [21]
<span>Photosynthesis Is a Reaction To Make Food</span>
7 0
3 years ago
CK-12 Boyle and Charles's Laws if Mrs. Pa pe prepares 12.8 L of laughing gas at 100.0 k Pa and -108 °C and then she force s the
nirvana33 [79]

Answer:

The answer to your question is   P2 = 2676.6 kPa

Explanation:

Data

Volume 1 = V1 = 12.8 L                        Volume 2 = V2 = 855 ml

Temperature 1 = T1 = -108°C               Temperature 2 = 22°C

Pressure 1 = P1 = 100 kPa                    Pressure 2 = P2 =  ?

Process

- To solve this problem use the Combined gas law.

                     P1V1/T1 = P2V2/T2

-Solve for P2

                     P2 = P1V1T2 / T1V2

- Convert temperature to °K

T1 = -108 + 273 = 165°K

T2 = 22 + 273 = 295°K

- Convert volume 2 to liters

                       1000 ml -------------------- 1 l

                         855 ml --------------------  x

                         x = (855 x 1) / 1000

                         x = 0.855 l

-Substitution

                    P2 = (12.8 x 100 x 295) / (165 x 0.855)

-Simplification

                    P2 = 377600 / 141.075

-Result

                   P2 = 2676.6 kPa

3 0
3 years ago
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