Question

Calculate the mass of ammonia (NH3) that contains a billion (1.00 * 10^12) hydrogen atoms.

Answer 1

Answer:

The mass of ammonia (NH3) that contains $1.00 \times 10^12$ hydrogen atoms is $9.4\times 10^{-12}$ g.

Explanation:

As $6.022\times 10^{23}$ atoms of hydrogen = 1 mole of the hydrogen atom

Therefore, $10^{12}$ atoms of hydrogen $= \frac{1}{6.022 \times 10^{23}}\times 10^{12}=1.66\times 10^{-12}$ moles of the hydrogen atom.

Now, there are 3 moles of hydrogen atoms in 1 mole of ammonia $(NH_3)$.

As the mass of 1 mole of ammonia is 17g, so

when there are 3 moles of hydrogen atoms, then the mass of ammonia = 17 g

Therefore, when there are $1.66\times 10^{-12}$ moles of hydrogen atoms, then the mass of ammonia $= \frac{17}{3}\times 1.66\times 10^{-12}=9.4\times 10^{-12$ g.

Hence, the mass of ammonia $(NH_3)$ that contains $1.00 \times 10^12$ hydrogen atoms is $9.4\times 10^{-12}$ g.