Answer:
Mass of iodine = 1954.26 g
Explanation:
Given data:
Mass of chlorine react = 546 g
Mass of iodine produced = ?
Solution:
Chemical equation:
2NaI + Cl₂ → 2NaCl + I₂
Number of moles of chlorine:
Number of moles = mass/molar mass
Number of moles = 546 g/71 g/mol
Number of moles = 7.7 mol
Now we will compare the moles of chlorine with iodine.
Cl₂ : I₂
1 : 1
7.7 : 7.7
Mass of iodine:
Mass = number of moles × molar mass
Mass = 7.7 mol × 253.8 g/mol
Mass = 1954.26 g
Answer:
13.7 moles
Explanation:
Given data:
Number of moles calcium carbonate = ?
Formula units calcium carbonate= 8.23 × 10²⁴
Solution:
The given problem will solve by using Avogadro number.
It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.
The number 6.022 × 10²³ is called Avogadro number.
For example,
18 g of water = 1 mole = 6.022 × 10²³ molecules of water
1.008 g of hydrogen = 1 mole = 6.022 × 10²³ atoms of hydrogen
For 8.23 × 10²⁴ formula units:
one mole = 6.022 × 10²³ formula units
8.23 × 10²⁴ formula units × 1 mole /6.022 × 10²³ formula units
13.7 moles
A petroleum-based lubricant used to in farming machinery.
hope i helped very well
