Question

Mya (m = 65 kg) floats 4 m from her spaceship (m = 1600 kg). What gravitational force would each mass exert on the other?

Answer 1

Answer:

ans: 4.34 × 10^(-9) N

Explanation:

mass of Mya say (m) = 65 kg

mass of spaceship say (M) = 1600 kg

universal gravitational constant(G) =6.67 × 10^(-11) Nm²/kg²

separation distance (d) = 4m

so,

gravitational force (F)= GMm/d²

=( 6.67 × 65 × 1600) / ( 10¹¹ × 4²)

= 4.34 × 10⁴ / 10¹³

= 4.34 × 10^(-9) N