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Vesna [10]
3 years ago
12

Mya (m = 65 kg) floats 4 m from her spaceship (m = 1600 kg). What gravitational force would each mass exert on the other?

Physics
1 answer:
Aleksandr-060686 [28]3 years ago
8 0

Answer:

ans: 4.34 × 10^(-9) N

Explanation:

mass of Mya say (m) = 65 kg

mass of spaceship say (M) = 1600 kg

universal gravitational constant(G) =6.67 × 10^(-11) Nm²/kg²

separation distance (d) = 4m

so,

gravitational force (F)= GMm/d²

=( 6.67 × 65 × 1600) / ( 10¹¹ × 4²)

= 4.34 × 10⁴ / 10¹³

= 4.34 × 10^(-9) N

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<h3>Answer:</h3>

49 N

<h3>Explanation:</h3>

<u>We are given;</u>

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  • The coefficient of friction as 0.6

We are required to determine the force that must be applied by the woman so the brick does not fall.

  • We need to importantly note that;
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The force of Earth's gravity on a capsule in space will lessen as it moves farther away. If the capsule moves to twice its dista
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Explanation:

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