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vampirchik [111]
3 years ago
14

Hai tiếp điểm hình trụ bằng đồng có đầu hình cầu bán kính R = 70mm, lực ép tiếp điểm F = 100N, Mô đun đàn hồi của đồng là 11.8 *

106(N/cm2). Cho biết: a = 0.86 * (F*R/E)1/3, điện trở suất của đồng là 1.62 * 10-8 (Ω/m), với tiếp điểm đồng thì hệ số K1 = 3,16.10-4 (ΩN1/2). Biết các giá trị ứng suất của đồng là: σdh = 38300 N/cm2; σdẻo = 45000 N/cm2; σd.Nát = 51000 N/cm2. Tính điện trở tiếp xúc trong trường hợp thỏa mãn điều kiện tản dòng lí tưởng và trong trường hợp thực nghiệm.
Physics
2 answers:
lisabon 2012 [21]3 years ago
6 0

Answer:

5dhydydyeze6ese6z7zuezuze6ezyezyezzeze

sukhopar [10]3 years ago
4 0
Yeah totally we get it
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What is occurring when two waves traveling along the same medium meet and cancel each other out?
timofeeve [1]

Answer:

Destructive interference

Explanation:

Destructive interference occurs when waves come together in such a way that they completely cancel each other out. When two waves interfere destructively, they must have the same amplitude in opposite directions.

6 0
3 years ago
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A red blood cell contains 4.8 107 free electrons. What is the total charge of these electrons in the red blood cell?
tatuchka [14]

Answer:

Charge, q=7.68\times 10^{-12}\ C

Explanation:

It is given that,

The number of electron in a RBCs, n=4.8\times 10^7

We need to find the total charge of these electrons in the red blood cell. Let it is q. Using the quantization of charge as follows :

q = ne

e is the change on electron

q=4.8\times 10^7\times 1.6\times 10^{-19}\\\\q=7.68\times 10^{-12}\ C

So, the net charge is 7.68\times 10^{-12}\ C.

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3 years ago
A cart travels 4.00 meters east and then4.00 meters north. determine the magnitude ofthe cart’s resultant displacement.
gogolik [260]
^
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|
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----------->|

Square root of (4^2 + 4^2) = 4*squareRoot(2)
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3 years ago
The instantaneous emf resulting from magnetic induction equals the rate of change of flux is
katen-ka-za [31]

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What is the strength of the electric field 3.0 cm from a small glass bead that has been charged to + 8.0 nc ?
Debora [2.8K]
Thinking the small glass bead as a single point charge, the electric field generated by it is given by
E(r) = k_e  \frac{Q}{r^2}
where
k_e = 8.99 \cdot 10^9 N m^2 C^{-2} is the Coulomb's constant
Q=8.0 nC=8.0 \cdot 10^{-9} C is the charge of the bead
r=3.0 cm=0.03 m is the distance at which we calculate the field.

Using these data, we find:
E=(8.99 \cdot 10^9 N m^2 C^{-2} ) \frac{(8.0 \cdot 10^{-9} C}{0.03 m)^2}=8.0 \cdot 10^4 N/C
6 0
3 years ago
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