Ethane is an alkane. Methane is also an alkane and is considered to be the simplest alkane. The difference is ethane has only 2 carbon. That carbon has 6 hydrogen attached to it. So what we do is we multiply the moles of ethane by the number of hydrogen (by dimension analysis) resulting to 82.68 moles H.
The number of moles of A4B3 produced in a reaction is obtained by stoichiometry.
The term stoichiometry refers to mass-mole relationship. The first step in solving this problem is by writing the correct reaction equation as follows;
4A + 3B -------> A4B3
If 4 moles of A yields 1 mole of A4B3
10 moles of A yields 10 * 1/4 = 2.5 moles of A4B3
Therefore, 2.5 moles of A4B3 is produced.
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Answer: Boiling the water
I hope this helped!
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A toxicity is answer for that question
Answer:
For 6.50 mol NaOH - 1.44M.
For 6.50 g NaOH - C. 0.0361 M
Explanation:
For 6.50 mol NaOH.
Molarity = moles solute/L solution = 6.5 mol/4.5 L solution = 1.44 mol/L=1.44M
There is no such answer in given choices.
For 6.50 g NaOH
M(NaOH) = 23 + 16 + 1 = 40 g/mol
Molarity = 6.5g* 1 mol/40g *1/4.5L = 0.0361 mol/L = 0.0361 M
There is such answer. It is C.
