I think the molecular formula would be CHO.
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Answer:
23 g of Zn will produce 0.352 mole of zinc chloride.
Explanation:
Given data:
mass of Zn = 23 g
Moles of ZnCl = ?
Solution:
Chemical equation:
2Zn + CuCl₂ → 2ZnCl + Cu
Number of moles of Zn:
<em>Number of moles of Zn = mass/ molar mass</em>
Number of moles of Zn = 23 g / 65.38 g/mol
Number of moles of Zn = 0.352 mol
now we will compare the moles of ZnCl with Zn because it is limiting reactant.
Zn : ZnCl
2 : 2
0.352 : 0.352
So 23 g of Zn will produce 0.352 mole of zinc chloride.
C. Must be touching the object
Given the values above, in order to know the molar concentration or the molarity of a solution containing 171 g of sucrose in 1.25L solution, here is the solution that you should follow: So,
MM = 342 (g/mol)
171 (g) / 342(g/mol) = x mol of sucrose
<span>x moles of sucrose/ 1.25 L = Molarity of solution
</span>Hope this is the answer that you are looking for.
Answer:
D. Solution A has more concentrated acid than solution B and acid in solution A is also a weaker acid than that in solution B.
Explanation:
As it has been said in the question that the volume to reach the equivalence point of the solution A is twice the volume of solution B, this is because the acid in the solution A is more concentrated than B that's why more NaOH was required to reach to the equivalence point.
Since the pH at the equivalence point was greater for solution A that means the acid in solution A was a weak acid that's why the pH raised more as the NaOH was added to the solution.
