Answer:
40 g/mol, Argon
Explanation:
We can find the number of moles of the gas by using the equation of state for an ideal gas:
![pV=nRT](https://tex.z-dn.net/?f=pV%3DnRT)
where
is the pressure of the gas at STP
is the volume of the gas
n is the number of moles
is the gas constant
is the absolute temperature of the gas at STP
Solving for n, we find:
![n=\frac{pV}{RT}=\frac{(101,300)(2.96\cdot 10^{-3})}{(8.314)(273)}=0.132 mol](https://tex.z-dn.net/?f=n%3D%5Cfrac%7BpV%7D%7BRT%7D%3D%5Cfrac%7B%28101%2C300%29%282.96%5Ccdot%2010%5E%7B-3%7D%29%7D%7B%288.314%29%28273%29%7D%3D0.132%20mol)
Now we can find the molar mass of the gas, which is given by
![M_m=\frac{m}{n}](https://tex.z-dn.net/?f=M_m%3D%5Cfrac%7Bm%7D%7Bn%7D)
where
m = 5.28 g is the mass of the gas
n = 0.132 mol is the number of moles
Substituting,
![M_m=\frac{5.28}{0.132}=40 g/mol](https://tex.z-dn.net/?f=M_m%3D%5Cfrac%7B5.28%7D%7B0.132%7D%3D40%20g%2Fmol)
So, the gas in this problem is Argon, which has a molar mass of 40 g/mol.
Answer:
Mass and speed.
Explanation:
From the formula k.e= ½mv². We can conclude that K.E depends on mass and speed of a body.
Answer:
C. A Spring Scale
Explanation:
Using process of elimination, we can quickly decide that a stopwatch and a ruler will not be useful in measuring the force. This leaves us with either the spring scale or a balance scale. A balance scale is used to compare two weights, so this is eliminated. That leaves us with a spring scale. This is because we can attached the spring scale to the car and when we let it go, we can record the force. I hope this helps!
Density
=mass÷volume
=19.67÷5.90
=3.33 g/ml