The wavelength of the first order bright band light light is 714 nm .
Explanation:
We have to find the wavelength of the first order brightness of a light. Here we are using Huygen's principle of light.
The formula is
nλ =d sinθ
where, n is the order of maximum
λ is the wavelength of light
d is the distance between the lines on diffraction grating.
θ is the angle.
For the given equation n is 1 because the problem states that the light forms 1st order bright band
λ is unknown.
d =
or 0.0000014 m
sin (30) = 0.5
so,
1(λ) = (0.0000014)(0.5)
= 0.0000000714
= 714 nm
Thus, The wavelength of the first order bright band light light is 714 nm .
Answer:
Electric Current
Explanation:
An electric current is defined as the flow of electrons through the wire and the components in a circuit.
This flow of electrons is caused by the presence of a battery, which creates a potential difference in the circuit. As a result of this potential difference, the electrons in the wire flow from the negative pole of the battery towards the positive pole (passing through the wire and the components of the circuit).
Bernoulli's principle of laminar/lamellar air flow, I think. High flow speed = low pressure, low flow speed = high pressure I think. So, the wings/aerofoils are designed to induce a low pressure on the top side of the wing and a high pressure on the underside of the wing, thus producing an "aerodynamic upthrust" (a static upthrust comes from an object in water via Archimedes) and LIFT.
Two "particles" of air one going topside and the other underside meet again at the end of their motion across the wing. So, top side has to travel faster than bottom side. So top side has a lower "dynamic pressure" than underside.
And all that for 5 points ????????? (If I'm right, of course ... )
private property owners in the United States can restrict public access to their land
Answer:
2.1844 m/s
Explanation:
The principle of conservation of momentum can be applied here.
when two objects interact, the total momentum remains the same provided no external forces are acting.
Consider the whole system , gun and bullet. as an isolated system, so the net momentum is constant. In particular before firing the gun, the net momentum is zero. The conservation of momentum,

assume the bullet goes to right side and the gravitational acceleration =10 
so now the weight of the rifle=

this is a negative velocity to the right side. that means the rifle recoils to the left side