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3 years ago

1.

2 answers:

4 0

I am about 99% sure, here are my answers
1. A, if you organize your data you are able to identify clusters of similar data
2. B, the data table will give the numerical values of your data while the bar graph will give a visual representation of your data
3. C, a line graph shows a cause and effect relationship

for number three, B is referring to a pie chart and D is referring to a bar graph

shutvik [7]3 years ago

4 0

1.A
2. C
3. D

I'm not sure that 2 is c. Hope this helps

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1.9 km converted to miles

Snowcat [4.5K]

When you convet km to miles this is what you get

1.18061

7 0

2 years ago

2. An airplane traveling north at 220. meters per second encounters a 50.0-meters-per-second crosswind

Alex777 [14]

The resultant speed of the plane is (3) 226 m/s

Why?

We can calculate the resultant speed of the plane by using the Pythagorean Theorem since both speeds are perpendicular (forming a right triangle).

So, calculating we have:

$ResultantSpeed=\sqrt{VerticalSpeed^{2}+HorizontalSpeed^{2}}\\\\ResultantSpeed=\sqrt{(220\frac{m}{s})^{2}+50\frac{m}{s})^{2}$

$ResulntantSpeed=\sqrt{48400\frac{m^{2} }{s^{2} }+2500\frac{m^{2} }{s^{2} } } \\\\ResultantSpeed=\sqrt{50900\frac{m^{2} }{s^{2} }}=226\frac{m}{s}$

Hence, we have that the resultant speed of the plane is (3) 226 m/s

Have a nice day!

5 0

2 years ago

Two long parallel wires 40 cm apart are carrying currents of 10 A and 20 A in the opposite direction. What is the magnitude of t

Alex_Xolod [135]

Answer:

The magnitude of the magnetic field halfway between the wires is 3.0 x 10⁻⁵ T.

Explanation:

Given;

distance half way between the parallel wires, r = ¹/₂ (40 cm) = 20 cm = 0.2 m

current carried in opposite direction, I₁ and I₂ = 10 A and 20 A respectively

The magnitude of the magnetic field halfway between the wires can be calculated as;

$B = \frac{\mu _oI_1}{2 \pi r} + \frac{\mu_oI_2}{2\pi r}$

where;

B is magnitude of the magnetic field halfway between the wires

I₁ is current in the first wire

I₂ is current the second wire

μ₀ is permeability of free space

r is distance half way between the wires

$B = \frac{\mu_o I_1}{2\pi r} + \frac{\mu_o I_2}{2\pi r} \\\\B = \frac{\mu_o }{2\pi r} (I_1 +I_2)\\\\B = \frac{4\pi *10^{-7} }{2\pi *0.2} (10 +20) = 3.0 *10^{-5}\ T$

Therefore, the magnitude of the magnetic field halfway between the wires is 3.0 x 10⁻⁵ T.

5 0

3 years ago

If you were to build a pipe organ with open-tube pipes spanning the range from 25 hz to 19 khz. The speed of sound in air is 343

Dennis_Churaev [7]

The length of the shortest pipe which is l2 will be 0.018m

<h3>What is Length?</h3>

This is defined as the measurement or extent of a substance from end to end. The formula is shown below:

L = v/f where v is speed , f is frequency

f1 = 25hz , f2 = 19khz

The length for both sides is seen below:

l1 = 343/25 = 13.72m

l2 = 343/19000 = 0.018m.

The length of the shortest pipe is therefore 0.018m.

Read more about Length here brainly.com/question/24259483

3 0

1 year ago

What is the net force on this object: F norm = 20N F frict = 14N F app = 22N F grav = 20N?

viva [34]

Answer:

8N i believe

Explanation:

4 0

2 years ago

Read 2 more answers