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bagirrra123 [75]
2 years ago
7

What is the temperature change that 725 g of aluminum will undergo when 2.35 x 104

Chemistry
1 answer:
Rashid [163]2 years ago
5 0

Answer:

36°C

Explanation:

Given parameters:

Mass of aluminum = 725g

Quantity of heat  = 2.35 x 10⁴J

Unknown:

Temperature change  = ?

Solution:

To solve this problem, we simply use the expression below:

  The quantity of energy is given as:

          Q  = m C Δt

Q is the quantity of energy

m is the mass

C is the specific heat capacity of aluminum  = 0.9J/g°C

Δt is the change in temperature

  The unknown is Δt;

             Δt  = \frac{Q}{mc}    = \frac{2.35 x 10^{4} }{725 x 0.9}    = 36°C

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It is common to mix polar solvents (e.g., acetone) with non-polar solvents (e.g., hexane) to obtain an eluting solvent of interm
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Answer:

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a solution with a transmittance of 0.44 is analyzed in a spectrophotometer with 6% stray light. calculate the absorbance reporte
IgorLugansk [536]

The absorbance reported by the defective instrument was 0.3933.

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True absorbance can be calculated by true transmittance, Tm = T+S(α-T)

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1 year ago
The half life of a certain radioactive element is 800 years. How old is an object if only 12.5% of radioactive atoms in it remai
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Given,  half life of a certain radioactive element = 800 years.

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Lets consider the initial amount of the radioactive substance  = 100%

Using the half life equation:

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where A₀ is the amount of radioactive substance at time zero and A is the amount of radioactive substance at time t, and t₁/₂ is the half-life of the radioactive substance.

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