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klasskru [66]
3 years ago
14

Please help he i will name brainliest!!!!!

Physics
1 answer:
goldenfox [79]3 years ago
6 0

Answer:

time is second

acceleration is speed

initial velocity is

distance is meters

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An inductor of inductance 0.02H and capacitor of capacitance 2 microF are connected in series to an AC source of frequency 200/p
Ad libitum [116K]
C because it’s not a or B so 50/50 c or d and d is def not the answer so c
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2 years ago
Whats the answer???????????
Leviafan [203]

Answer: Less than 4 ohms

Explanation:

We have three resistors with the following resistance:

R_{1}=4\Omega

R_{2}=6\Omega

R_{3}=8\Omega

Now, when the resistors are connected in parallel, the total resistance R is calculated as follows:

\frac{1}{R}=\frac{1}{R_{1}}+\frac{1}{R_{2}}+\frac{1}{R_{3}}

Isolating R:

R=\frac{R_{1}R_{2}R_{3}}{R_{3}(R_{1}+R_{2})+R_{1}R_{2}}

Rewriting with th known values:

R=\frac{(4\Omega)(6\Omega)(8\Omega)}{8\Omega(4\Omega+6\Omega)+(4\Omega)(6\Omega)}

Finally:

R=1.84 \Omega

Hence, the correct option is less than 4 ohms.

4 0
3 years ago
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8 0
3 years ago
What is the resistance of a bulb of 4ow<br>connected in a line of 220v?<br>2​
inn [45]

Answer:

1210 ohm

Explanation:

Given :

P=40 W

V=220 V

Now,

P=\frac{V^{2} }{R} \\40=\frac{(220)^{2} }{R} \\40R=48400\\R=\frac{48400}{40} \\R=1210 ohm

Therefore, resistance of bulb will be 1210 ohm

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2 years ago
An engineer is investigating potential energy with two
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