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NeX [460]
3 years ago
14

What is your REASONING for this CLAIM? EXPLAIN WHY your claim is true.

Physics
2 answers:
Vanyuwa [196]3 years ago
7 0
Kinetic energy is energy in motion (movement). Energy transfer is the process by which energy is relocated from one system to another, for example, through the transfer of heat, work or mass transfer. (Not really sure what the question this)
zloy xaker [14]3 years ago
5 0

Answer:

IV: speed of the fan

DV: time of cup ascent

Explanation:

Kinetic energy is the energy of mass in motion. The kinetic energy of an object is the energy it has because of its motion. As the speed of the fan increases, so does the kinetic energy, then it transfers energy to the Cup ascent.

You might be interested in
What happens to electron flow with a conductor of the voltage source is removed?
9966 [12]
The electrons stop flowing
4 0
3 years ago
What statement about energy transfer in a wave is true?
laila [671]

Answer:

Energy moves between the particle of the medium.

Explanation:

8 0
3 years ago
Which of the following is a difference between electromagnetic waves and sound waves?
Paul [167]

Answer:

D

Explanation:

A is wrong as otherwise the ocean would be black as light could not pass through it to create images.

B is wrong. This is a weird one as the electromagnetic spectrum attached below shows that radio waves have the least amount of energy vs gamma which has the highest and you can't really compare this to sound waves.

C just straight up false.

D is correct, no way to remember this, just learn it. a couple of facts about transverse waves of google. Electromagnetic waves are a type of transverse waves.  These waves do not require a medium to travel.  As the name of the waves imply, these waves show electrical and magnetic properties.  No any charge occur in the waves.  Electromagnetic waves work by the laws of reflection and refraction.  They travel as straight lines in a vacuum at a speed of 3 x 10 8 ms -1.

Extra info:

As gamma waves have the highest energy it means that the waves are closer together (the wavelength is smaller) and they create more heat. Also gamma waves go through everything, X-ray only through skin and bounces of dense things like bones, which creates images. These eventually weaken more and more until radio waves do not pass through anything and just bounces around and everywhere which allows you to gain more coverage on a radio then on a cell phone.

7 0
3 years ago
A woman (mass= 50.5 kg) jumps off of the ground, and comes back down to the ground at a velocity of -8.4 m/s.
Blizzard [7]

Answer:

Approximately 1.6\times 10^{3}\; \rm N.

Explanation:

By the Impulse-Momentum Theorem, the change in this woman's momentum  will be equal to the impulse that is applied to her.

The momentum p of an object is equal to the product of its mass m and velocity v. That is: p = m \cdot v.

Let v(\text{before}) and v(\text{after}) represent the velocity of the woman before and after the landing. Let m represent the woman's mass.

  • The woman's momentum before the landing would be m \cdot v(\text{before}).
  • The woman's momentum after the landing would be m \cdot v(\text{after}).

Therefore, the change in this woman's momentum would be:

\begin{aligned}& \Delta p \\ & = p(\text{after}) - p(\text{before}) \\ &= m \cdot (v(\text{after})- v(\text{before}))\end{aligned}.

On the other hand, impulse is equal to force multiplied by the duration of the force. Let F represent the average force on the woman. The impulse on her during the landing would be F \cdot t.

Apply the Impulse-Momentum Theorem.

  • Impulse: F\cdot t.
  • Change in momentum: m \cdot (v(\text{after})- v(\text{before})).

Impulse is equal to the change in momentum:

F \cdot t = m \cdot (v(\text{after})- v(\text{before})).

After landing, the woman comes to a stop. Her velocity would become zero. Therefore, v(\text{after}) = 0\; \rm m \cdot s^{-1}.

\begin{aligned}F &= \displaystyle \frac{m \cdot (v(\text{after})- v(\text{before}))}{t} \\ &= \frac{50.5\; \text{kg} \times \left(0 \; \mathrm{m \cdot s^{-1}}- 8.4\; \mathrm{m \cdot s^{-1}}\right)}{0.27\; \rm s} \\ &\approx 1.6 \times 10^{3}\; \rm N\end{aligned}.

3 0
4 years ago
Physicists often measure the momentum of subatomic particles moving near the speed of light in units of MeV/c, where c is the sp
maxonik [38]

Answer:

kg m/s

Explanation:

e = Charge = C

V = Voltage = \dfrac{N}{C}m

c = Speed of light = m/s

Momentum is given by

\dfrac{MeV}{c}=\dfrac{e\times V}{c}\\\Rightarrow \dfrac{MeV}{c}=\dfrac{C\times \dfrac{N}{C}\times m}{m/s}\\\Rightarrow \dfrac{MeV}{c}=Ns\\\Rightarrow \dfrac{MeV}{c}=kg\times \dfrac{m}{s}\times s\\\Rightarrow \dfrac{MeV}{c}=kg\cdot m/s

The unit of MeV/c in SI fundamental units is kg m/s

5 0
3 years ago
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