The correct answer is false.
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Answer:
We need 6.0 moles of aluminium
Explanation:
Step 1: Data given
Number of moles of H2 = 9.0 moles
Step 2: The balanced equation
2 Al + 6 HCl → 2 AlCl3 + 3H2
Step 3: Calculate moles Al
For 2 moles Aluminium, we need 6 moles HCl to produce 2 moles AlCl3 and 3 moles H2
For 9.0 moles of H2 we need 2/3 * 9.0 = 6.0 moles of aluminium
We need 6.0 moles of aluminium
Number of electron in O = 8
So, in O2 it would be: 8 * 2 = 16
So, your final answer is 16
Hope this helps!
<span>Answer:
Nothing is balanced in your final equation: not H, not O, not Cr, not I and your charges aren't either.
Start with your 2 half reactions:
I- --> IO3-
Cr2O72- --> 2 Cr3+
Balance O by adding H2O:
I- + 3 H2O --> IO3-
Cr2O72- --> 2 Cr3+ + 7H2O
Balance H by adding H+:
I- + 3 H2O --> IO3- + 6 H+
Cr2O72- + 14 H+ --> 2 Cr3+ + 7H2O
Balance charge by adding e-:
I- + 3 H2O --> IO3- + 6 H+ + 6 e-
Cr2O72- + 14 H+ + 6 e- --> 2 Cr3+ + 7H2O
Since the numbers of electrons in your two half reactions are the same, just add them and simplify to give:
Cr2O72- + I- + 8 H+ --> IO3- + 2 Cr3+ + 4 H2O</span>
