Answer:
Number of moles of Fe = 10 mol
Number of moles of CO₂ = 15 mol
Explanation:
Given data:
Number of moles of iron oxide = 5 mol
Number of moles of carbon monoxide = 25 mol
Number of moles of product = ?
Solution:
Fe₂O₃ + 3CO → 2Fe + 3CO₂
Now we will compare the moles of reactant with product.
Fe₂O₃ : Fe
1 : 2
5 : 2×5 = 10 mol
Fe₂O₃ : CO₂
1 : 3
5 : 3×5 = 15 mol
CO : Fe
3 : 2
25 : 2/3×25 = 16.7 mol
CO : CO₂
3 : 3
25 : 25
Less number of moles of Fe and CO₂ are formed by iron oxide thus it will act as limiting reactant while CO is inn excess.
Explanation:
Energy makes molecules in the air move faster and expand, decreasing density. The opposite is true for cold air. Molecules are closer together, and absorb less energy.
The heat will flow from copper to aluminum because Cu is at higher temperature. The heat liberated is -7.60kJ
When two metals at different temperatures are kept in contact, heat flows from hotter metal to colder metal until thermal equilibrium is reached.
Here Copper is at a temperature of 60 degree Celsius and aluminum is at 40 degree Celsius. Thus, heat will flow from Cu to Al.
In order to calculate the amount of heat liberated following calculations are required.
m1=262 g
T1=87 oC
Cp=0.385 J/g oC
T2=11.8 oC
The heat liberated can be expressed as follows:
Q=mCp(T2-T1)
Q=262 g*0.385 J/goC(11.8-87)oC
Q=-7585 J
=-7.60kJ
To learn more about heat check the link below:
brainly.com/question/13439286
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To rank the effective nuclear charge Z* experienced by a valence electrons of a set of atoms that belong to a same period, you only need to apply the rule of trend: it increases as you move from left to right in the period.
So, lets do it for these atoms: P, Al, Si, Cl
The belong to a same period and the order is Al, Si, P, Cl (just see a periodic table). So the rank is Al < Si < P < Cl
Now, lets do it for these atoms:, Be, Ne, O, C
They belong to the second period. The order is Be, C, O, Ne
So, the rank is Be < C < O < Ne.
