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inna [77]
3 years ago
5

Which of the following experiments raises ethical concerns

Chemistry
1 answer:
xxMikexx [17]3 years ago
6 0

Answer:

Research that releases a poisonous gas into the air.

Explanation:

Since I don't know the options I will guess it is ^

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10. At 573K, NO2(g) decomposes forming NO and O2. The decomposition reaction is second order in NO2 with a rate constant of 1.1
leva [86]

Answer:

48.67 seconds

Explanation:

From;

1/[A] = kt + 1/[A]o

[A] = concentration at time t

t= time taken

k= rate constant

[A]o = initial concentration

Since [A] =[A]o - 0.75[A]o

[A] = 0.056 M - 0.042 M

[A] = 0.014 M

1/0.014 = (1.1t) + 1/0.056

71.4 - 17.86 = 1.1t

53.54 = 1.1t

t= 53.54/1.1

t= 48.67 seconds

Hence,it takes 48.67 seconds to decompose.

6 0
3 years ago
Which of these is a source of sediment?
WINSTONCH [101]
I do believe the answer is A. I'm sure
7 0
3 years ago
Read 2 more answers
If Matteo has a model car with a volume of 100 mL and a mass of 200 g, what is the density of their model car?
OLEGan [10]

Answer:

<h2>2 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume}  \\

From the question we have

density =  \frac{200}{100}  \\

We have the final answer as

<h3>2 g/mL</h3>

Hope this helps you

6 0
3 years ago
4. 200 mL of a 5.6M solution to BaCl_2 have 750 mL of water added to it. What is the new concentration?
IceJOKER [234]

Answer:

4. 1.18 mol·L⁻¹

14. See below.

Explanation:

4. Dilution calculation

V₁c₁ = V₂c₂

Data:

V₁ = 200 mL; c₁ = 5.6 mol·L⁻¹

V₂ = 950 mL; c₂ = ?

Calculation:

c₂ = c₁ × V₁/V₂

c₂ = 5.6 mol·L⁻¹ × (200/950) = 1.18 mol·L⁻¹

The new concentration is 1.18 mol·L⁻¹ .

14. Boyle's Law graphs

We can write Boyle's Law as

pV = k or p = k/V or V= k/p

p and V are inversely related.

(a) As pressure increases, volume decreases. Thus, a graph of V vs p is a hyperbola.

(b) p = k/V =k(1/V)

 1/V = (1/k)p

   y  =   m x  + 0

A graph of 1/V vs p is a straight line.

4 0
3 years ago
How many moles are in 68.5 liters of oxygen gas at STP?
g100num [7]
We can solve this problem when we use the conditions of a gas at standard temperature and pressure. It has been established that at STP where the temperature is 0 degrees Celsius and the pressure is 101.325 kPa, the volume of 1 mole of gas is 22.4 L. We will use this data for the calculations.

68.5 L ( 1 mol O2 / 22.4 L O2 ) = 3.06 mol O2
7 0
3 years ago
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