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Marysya12 [62]
3 years ago
14

A box is pulled to the right with a force of 65 N at an angle of 58 degrees to the horizontal. The surface is frictionless. The

free body diagram is shown. What is the net force in the x-direction?
Physics
2 answers:
Citrus2011 [14]3 years ago
5 0
The free-body diagram is missing, but I assume the only forces acting on the box are the force F pushing the box, the weight of the object and the normal reaction of the surface.

Since the weight and the normal reaction acts in the vertical (y) direction, the only force acting on the box in the horizontal (x) direction is the horizontal component of the force F, which is given by
F_x = F \cos 58^{\circ} = (65 N)(\cos 58^{\circ} )=34.4 N
And so this is the net force in the x-direction.
Alex787 [66]3 years ago
3 0

Answer:

34 N

Explanation:

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Answer:

Energy. They need energy.

Explanation:

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3 years ago
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Compute the expected shell-model quadrupole moment of 209Bi () and compare with the experimental value, - 0.37 b
Over [174]

Answer:

0.22 b

Explanation:

Quadrupole moment of the nucleon is,

Q=-\frac{2j-1}{2(j+1)}\frac{3}{5}R^{2}

And also,

R^{2}=R^{2} _{0}A^{\frac{2}{3} }

And, R _{0}=1.2\times 10^{-15}m

Now,

Q=-\frac{2j-1}{2(j+1)}\frac{3}{5}R^{2} _{0}A^{\frac{2}{3} }

For Bismuth j=\frac{9}{2} and A is 209.

Q=-\frac{2\frac{9}{2} -1}{2(\frac{9}{2} +1)}\frac{3}{5}(1.2\times 10^{-15}) ^{2}(209)^{\frac{2}{3} }\\Q=0.628\times 35.28\times 10^{-30} \\Q=22.15\times 10^{-30} m^{2} \\Q=0.2215\times 10^{-28} m^{2} \\Q=0.22 barn

Therefore, the expected value of quadrupole is 0.22 b which is quite related with experimental value which is 0.37 b

3 0
3 years ago
How would the photos set up change the mechanical advantage of lifting the block as compared with lifting the block without a le
lisabon 2012 [21]
<h3>Answer:</h3>

  The mechanical advantage would decrease, making the block more difficult to lift.

<h3>Explanation:</h3>

The mechanical advantage in such a setup is the ratio of distance from A to B to the distance from D to B. In this picture, that ratio is less than 1, meaning the advantage of having this setup is less than the advantage of no setup at all.

While the force required to lift the block is increased by this setup, the distance over which that force is applied will be smaller for raising the block to a given height. (Overall, for the same height, more work is required with the lever setup because you're raising part of the mass of the lever as well as the mass of the block.)

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aliina [53]
The answer is a Viscosity because it describes the internal friction of a moving liquid
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3 years ago
Un cable está tendido sobre dos postes colocados con una separación de 10 m. A la mitad del cable se cuelga un letrero que provo
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Answer:

El peso del cartel es 397,97 N

Explanation:

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La posición del letrero en el cable = En el medio = 5

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El peso del signo = 397,97 N.

8 0
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