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Pie
3 years ago
9

Type your answer in the box.

Physics
1 answer:
aliina [53]3 years ago
4 0
The answer is a Viscosity because it describes the internal friction of a moving liquid
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Energy is released from ATP when
velikii [3]

Answer:

B

Explanation:

After ATP is transfered energy, it will turn into ADP (adenosine diphosphate) that means two phosphate bond, compared to ATP(adenosine triphosphate), ADP has one bond lesser than ATP

5 0
4 years ago
Which simple machine is described as an inclined plane wrapped around a cylinder?
Ad libitum [116K]

Answer:

A screw.

Explanation:

3 0
3 years ago
Read 2 more answers
A force of 333 N is applied 33 cm from the pivot point. What is the maximum torque of this situation
exis [7]

Answer: 109.89 Nm

Explanation:

The maximum torque will be calculated as the force multiplied by the perpendicular distance. This will be:

Torque = force × perpendicular distance

torque = 333 × 0.33

= 109.89 Nm

5 0
3 years ago
The intensity of a sound wave increases as the wave spreads out from the source of the sound. True or false
ludmilkaskok [199]

Answer:False

Explanation:

the intensity of the sound wave decreases with increasing distance from the source.

3 0
3 years ago
A block of mass 0.404 0.404 kg is hung from a vertical spring and allowed to reach equilibrium at rest. As a result, the spring
VARVARA [1.3K]

To solve this problem it is necessary to apply the concepts related to the Force from Hook's law as well as the definition of the period provided by the same definition.

We know that the Force can be defined as

F = xk \rightarrow mg = kx \Rightarrow k = \frac{mg}{x}

Where

k = Spring constant

x = Displacement

g = Gravity

m = mass

At the same time the period of a spring mass system is defined as

T = 2\pi \sqrt{\frac{m}{k}}

Where

m = Mass

k = Spring constant

Our values are given as,

m = 0.404kg

x = 0.666m

Replacing to find the value of the Spring constant we have that

k = \frac{mg}{x}

k = \frac{(0.404)(9.8)}{0.666}

k = 5.944N/m

Now using the formula of the period we know that

T = 2\pi \sqrt{\frac{m}{k}}

T = 2\pi \sqrt{\frac{0.404}{5.944}}

T = 1.638s

Finally, if the oscillation was 0.359m

The maximum height will be determined by the total length of that oscillation being equivalent to

h=2a

h = 2*0.359

h = 0.718m

4 0
3 years ago
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