Question

A 10 µf capacitor is charged to 108 v and is then connected across a 328 ω resistor. what is the initial charge on the capacitor? answer in units of µc.

Answer 1

The capacitance is defined as the maximum charge stored in a capacitor, Q, divided by the voltage applied, V:
$C= \frac{Q}{V}$

The capacitor is initially charged with the battery of 108 V, so the the initial charge on the capacitor can be found by re-arranging the previous formula:
$Q=CV=(10 \mu F)(108 V)=1080 \mu C$