Answer: 0.85075J/g.K
Explanation:
Mass of the material = 100g
Energy (Q) = 5104.5J
T1 = 20°C = 293K
T2 = 80°C = 353K
Formula for heat energy (Q) = mc ∇T
Q = mc∇T
∇T = T2 - T1
∇T = 353K - 293K = 60K
Q = mc∇T
C = Q / m∇T
C = (5104.5) / (100 * 60)
C = 0.85075 J/gK
The specific heat capacity of the material is 0.85075J/gK.
Answer:
D) 3.51x10²³ formula units
Explanation:
To know this, we need to calculate the molecular mass of CaO. To do that, let's use the atomic mass of each element of this compound.
Ca: 40.08 g/mol; O: 16 g/mol
With these given AM, let's calculate the molar mass of CaO:
Mm CaO = 40.08 + 16 = 56.08 g/mol
Now that we have the MM of CaO, it's time to determine the moles of CaO:
moles = mass / MM
moles = 32.7 / 56.08 = 0.5831 moles
Finally to get the formula units, we need to use the Avogadro's number which is 6.02x10²³. According to this number, 1 mole of any substance has this number of atoms, molecules or formula units. So, if we have 0.5831 moles, then the formula units will be:
FU = 0.5831 * 6.02x10²³
<h2>
FU = 3.51x10²³ formula units</h2>
Hope this helps
