In general, ionic compounds have

A newspaper story describing the local celebration of Mole Day on October 23 (selected for Avogadro's number, 6.02 X 10^ 23 ) at

stepladder [879]

Answer:

The answer is "670.176 km".

Explanation:

Volume of the occupies of one M & M= 0.5 \ cm^3\\\\

M&M 1 mole $= 6.02 \times 10^{23}\\\\$

Calculating volume of M& M mole $= 0.5 \ cm^3 \times 6.02 \times 10^{23}=3.01 \times 10^{23}\ cm^3\\\\$

Calculating the cube mole $L^3= 3.01 \times 10^{23}\ cm^3\\\\$

$L=6.70176 \times 10^{7}\ cm\\\\$

$=6.70176 \times 10^{7}\ cm \times \frac{1\ m}{100\ cm}\\\\=670176\ m\\\\=670.176 \ km$

Therefore 18 tractor trailers wouldn't be sufficient.

8 0

3 years ago

Which ion of nitrogen is smaller: N3+ or N5+?

lakkis [162]

Answer:

N3+ is ion of nitrogen is smaller

8 0

3 years ago

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PLEASE HELP WILL GIVE BRAINLIEST

Gnom [1K]

Answer:

2. Option B.

Explanation:

H₂SO₄ + Ba(OH)₂ → BaSO₄ + 2H₂O

You can count 2H in sulfuric acid and 2 H in the barium hyrdoxide, so the coefficient for water must be 2.

You will have 4 H on both sides of the reaction.

Try with the dissociations of each reactant

Sulfuric acid ⇒ H₂SO₄ → 2H⁺ + SO₄⁻²

Barium hydroxide ⇒ Ba(OH)₂ → Ba²⁺ + 2OH⁻

Sulfate anion bonds to barium cation to produce the salt, therefore the 2 protons will bond the 2 hydroxide in order to produce, 2 moles of H₂O

2H⁺ + 2OH⁻ → 2H₂O

8 0

3 years ago

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Signs of a chemical change

dezoksy [38]

Answer: There are five signs of chemical change

Color Change
Production of an odor
Change of Temperature
Evolution of Gas (bubbles start to form)
Precipitate (starts to form a solid)

When these signs start to form you know chemical change is at work.

Hope this helps :)

5 0

4 years ago

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Instant cold packs, often used to ice athletic injuries on the field, contain ammonium nitrate and water separated by a thin pla

RSB [31]

<u>Answer:</u> The enthalpy change of the reaction is -27. kJ/mol

<u>Explanation:</u>

To calculate the mass of water, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

Density of water = 1 g/mL

Volume of water = 25.0 mL

Putting values in above equation, we get:

$1g/mL=\frac{\text{Mass of water}}{25.0mL}\\\\\text{Mass of water}=(1g/mL\times 25.0mL)=25g$

To calculate the heat released by the reaction, we use the equation:

$q=mc\Delta T$

where,

q = heat released

m = Total mass = [1.25 + 25] = 26.25 g

c = heat capacity of water = 4.18 J/g°C

$\Delta T$ = change in temperature = $T_2-T_1=(21.9-25.8)^oC=-3.9^oC$

Putting values in above equation, we get:

$q=26.25g\tiimes 4.18J/g^oC\times (-3.9^oC)=-427.9J=-0.428kJ$

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of ammonium nitrate = 1.25 g

Molar mass of ammonium nitrate = 80 g/mol

Putting values in above equation, we get:

$\text{Moles of ammonium nitrate}=\frac{1.25g}{80g/mol}=0.0156mol$

To calculate the enthalpy change of the reaction, we use the equation:

$\Delta H_{rxn}=\frac{q}{n}$

where,

q = amount of heat released = -0.428 kJ

n = number of moles = 0.0156 moles

$\Delta H_{rxn}$ = enthalpy change of the reaction

Putting values in above equation, we get:

$\Delta H_{rxn}=\frac{-0.428kJ}{0.0156mol}=-27.44kJ/mol$

Hence, the enthalpy change of the reaction is -27. kJ/mol

4 0

4 years ago