Hope you could get an idea from here.
Doubt clarification - use comment section.
It is in the form y = mx + b. therefore it is linear.
Start by completely ignoring the paralelagram.
Let's choose the top triangle as our starter.
To get the top triangle to the position of the bottom triangle, you must translate it.
First, find how many units the first triangle must move down to reach the same level as the bottom triangle, (i'll let you figure it out bu numbering this as a question) 1.<u> </u>
Next, your first triangle should need to move left to reach the position of the second triangle. How many units left does the first triangle need to move?
2.<u> </u>
<u>You moved the first triangle *Blank* units down and *Blank* units left.</u>
Lastly, you need to look at your paralelagram.
Take the same movements you did with the two triangles and transfer them to the nessacary point of the paralelagram.
<em><u>If you need and extra help, or need more explanation, ask in the comments section. I also recomend that you tell me what you got as your answers to one and two so that you can make sure you got the answer correct.</u></em>
1 is the answer 1111111111
Answer:
the answer 0.4
Step-by-step explanation;
