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ehidna [41]
3 years ago
13

An 8 oz. bottle of energy drink contains 6.0 g of protein, 2.0 g of fat, and 16.3 g of carbohydrate. The fuel value of this ener

gy drink bottle is ________ kJ. The fuel values for protein, fat, and carbohydrate are 17, 38, and 17 kJ/g, respectively.
a. 280
b. 720
c. 72
d. 460
e. 520
Chemistry
1 answer:
valina [46]3 years ago
4 0

<u>Answer:</u> The correct option is d) 460 kJ

<u>Explanation:</u>

We are given:

Content of fat in energy drink = 2.0 g

Content of protein in energy drink = 6.0 g

Content of carbohydrate in energy drink = 16.3 g

Also,

The fuel value of fat = 38 kJ/g

The fuel value of protein = 17 kJ/g

The fuel value of carbohydrate = 17 kJ/g

So, the fuel value of the energy drink will be:

Total fuel value = (2.0g\times 38 kJ/g)+(6.0g\times 17 kJ/g)+(16.3g\times 17 kJ/g)

Total fuel value = [76+102+277]=460kJ

Hence, the correct option is d) 460 kJ

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<u>Answer:</u> The correct answer is option A.

<u>Explanation:</u>

To calculate the volume of an object, we use the formula:

Density=\frac{\text{Mass of an object}}{\text{Volume of an object}}

We are given:

Density of an object = 24.5g/cm^3

Mass of an object = 8.2 grams

Volume of an object = ?

Putting values in above equation, we get:

24.5g/cm^3=\frac{8.2g}{Volume}

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Given

Mass of NO - 824 g

Molar mass of NO - 30.01g/mol

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The charge of Br changed from –1 to 0, therefore it is the element which is oxidized. Since it is oxidized then Br is also the reducing agent.

 

The charge of Mn changed from +4 to +2 therefore it is the element which is reduced. Since Mn is reduced, then MnO2 is the oxidizing agent.

 

The half –reactions are:

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