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Delicious77 [7]
3 years ago
9

Which of the following is true about mixtures and compounds? A compound forms when different substances chemically combine to fo

rm a new substance. A mixture contains different substances that are not chemically combined with one another. Mixtures and compounds are both made of two or more different substances. all of these
Chemistry
2 answers:
Musya8 [376]3 years ago
6 0
All of these are true
Monica [59]3 years ago
3 0
All of them are true.
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What occurs to the atoms of reactants in a chemical reaction?

Answer:

In a chemical reaction, the atoms and molecules that interact with each other are called reactants. ... No new atoms are created, and no atoms are destroyed. In a chemical reaction, reactants contact each other, bonds between atoms in the reactants are broken, and atoms rearrange and form new bonds to make the products.

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2 years ago
Can you classify solid and liquid please
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Answer:

Solid : The intermolecular space is very less

Liquid : The intermolecular space is fairly more than in solids

Solid : It has a fixed shape

Liquid : It has a fixed volume but shape changes according to where it is placed

Solid : eg : Books

Liquid : eg : water

If my answer helped, kindly mark me as the brainliest!!

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3 years ago
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5 0
3 years ago
A rubber ball is held 4.0 m above a concave spherical mirror with a radius of curvature of 1.5 m. At time equals zero, the ball
exis [7]

The time elapsed when the ball placed above the concave mirror and the image formed would be at the same location is 0.55 s.

<h3>Image distance</h3>

The position of the image formed is determined using the followimg mirror formula;

\frac{1}{f} = \frac{1}{v} + \frac{1}{u}

where;

  • f is the focal length of the mirror
  • v is the image distance
  • u is the object distance

f = R/2

f = 1.5/2

f = 0.75 m

When the ball and its image is in the same position, u = v

The position of the ball is calculated as;

\frac{1}{f} = \frac{1}{u} + \frac{1}{u} \\\\\frac{1}{f} = \frac{2}{u} \\\\u = 2f\\\\u = 2(0.75)\\\\u = 1.5 \ m

<h3>Time of motion of the ball</h3>

The time taken for the ball to travel the caluclated distance is determined as;

h = ut + ¹/₂gt²

1.5 = 0  + ¹/₂(9.8)t²

1.5 = 4.9t²

t² = 1.5/4.9

t² = 0.306

t = 0.55 s

Thus, the time elapsed when the ball and its image are at the same location is 0.55 s.

Learn more about concave mirror here: brainly.com/question/7512320

8 0
2 years ago
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