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2 years ago

Consider the given acid ionization constants. identify the strongest conjugate base.

2 answers:

7 0

The question is incomplete. Complete question is:
<span>Consider the given acid ionization constants. identify the strongest conjugate base.
</span>HNO2(aq) 4.6×10−4
HCHO2(aq) 1.8×10−4
HClO(aq) 2.9×10−8
HCN(aq) 4.9×10−10
.........................................................................................................................
Correct Answer: option 4: HCN(aq) 4.9×10−10

Reason:
According to Lowry and Bronsted theory of acid and base. Stronger the acid, weaker will be the conjugate base.

In present case, ionization constant is highest of HCN i.e. 4.9× $10^{-10}$ . This signifies that, it is the strongest acid. Hence, conjugate base associated with this acid (i.e. $CN^{-}$ ) is the weakest.

stealth61 [152]2 years ago

4 0

Missing question:
<span>HNO2(aq) 4.6×10−4
HCHO2(aq) 1.8×10−4
HClO(aq) 2.9×10−8
HCN(aq) 4.9×10−10
</span>Answer is:<span> the strongest conjugate base is CN</span>⁻(aq), because it has highest base ionization constant.
Chemical reaction: HCN(aq) ⇄ CN⁻(aq) + H⁺(aq).
Ka(HCN) = 4,9·10⁻¹⁰.
Ka · Kb = Kw; ionic product of water.
Kb = Kw ÷ Ka.
Kb(CN⁻) = 1·10⁻¹⁴ 4,9·10⁻¹⁰.
Kb(CN⁻) = 2,04·10⁻⁵.

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When solutions of silver nitrate and sodium chloride are mixed, silver chloride precipitates out of the solution according to th

kipiarov [429]

The concentration of the sodium chloride would be 0.082 M

<h3>Stoichiometric calculations</h3>

From the equation of the reaction, the ratio of AgCl produced to NaCl required is 1:1.

Mole of 46.6 g AgCl produced = 46.6/143.32 = 0.325 moles

Equivalent mole of NaCl = 0.325 moles.

Molarity of 0.325 moles, 3.95 L NaCl = mole/volume = 0.325/3.95 = 0.082 M

More on stoichiometric calculations can be found here: brainly.com/question/27287858

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1 year ago

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What is some fun facts about the person who started Sand Storms? What can be the worst in a Sand Storms? If you were caught in o

Dahasolnce [82]

Answer:

The clouds that carry the dust can be huge, and miles long. They can rise to be over 305m. They also have wind speeds of at least 40 kilometers.Sandstorms can happen really quickly.

Explanation:

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Other immediate effects of sandstorms to me include the worsening of lung functions if I have asthma. Due to inhalation of large amounts of dust, dust pneumonia could be developed. Diseases such as silicosis could also develop from prolonged exposure to sand. If left untreated, it will eventually lead to asphyxiation and lung cancer. The eyes could also be affected by the particles. Keratoconjunctivitis sicca, or dry eyes, could develop which could lead to blindness. My exposure to sandstorms could have adverse effects on my circulatory system. So I could either die immediately or fall terrible sick it depend on my health issue.

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2 years ago

(6 points) Calculate the maximum number of moles and grams of H2S that can form when 158 g of aluminum sulfide reacts with 131 g

Schach [20]

Answer:107.1 g, 124.1 g

Explanation:

The equation of the reaction is;

Al2S3(s) + 6H20(l) ----> 2Al(OH)3(s) + 3H2S(g)

Hence;

For Al2S3

Number of moles= reacting mass/molar mass

Number of moles = 158g/150gmol-1 =1.05 moles

If 1 mole of Al2S3 yields 3 moles of H2S

1.05 moles of Al2S will yield

1.05 × 3/1 = 3.15 moles

Mass of H2S = 3.15moles × 34 gmol-1 = 107.1 g

For water

Number of moles of water = 131g/18gmol-1= 7.3 moles

6 moles of water yields 3 moles of H2S

7.3 moles of water will yield 7.3 × 3/6 = 3.65 moles of H2S

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2 years ago

At a certain temperature the vapor pressure of pure methanol is measured to be . Suppose a solution is prepared by mixing of met

CaHeK987 [17]

Answer:

Partial pressure is 0.13 atm

Explanation:

CHECK THE COMPLETE QUESTION BELOW :

At a certain temperature, the vapor pressure of pure methanol is measured to be 0.43atm. Suppose a solution is prepared by mixing 88.2 g of methanol and 116.g of water. Calculate the partial pressure of methanol vapor above this solution. Be sure your answer has the correct number of significant digits. Note for advanced students: you may assume the solution is ideal.

Using Raoult´s law for ideal soultions we have

P(A) = X(A) *Pº(A)

where P(A) is the partial vapor pressure pressure of methanol,

X(A) is the mole fraction of solute (methanol) in solution,

Pº(A) is the vapor pressure of pure solute

Raoult's law states that the vapor pressure of a solution is dependent on the mole fraction of a solute added to the solution.

Raoult's law can be expressed below

Psolution = ΧsolventP0solvent.

Expressing it interns of the constituents given in the question we have

P(CH₃OH) = X(CH₃OH) x Pº(CH₃OH)

To calculate the mole fraction of CH₃OH, we make use of the formula below :

X(A) = mol (A) / ntotal

Ntotal = (sum of number of moles of A )+( moles solvent)

mol (CH₃3OH) can be calculated as :: 88.2 g/ 32 g/mol = 2.76 mol of CH₃OH

mol (H₂O) can be calculated as ::116 g/ 18 g/mol = 6.44 mol

total n = (6.44 + 2.76) mol = 9.20 mol

To calculate the partial pressure the we say;

P(CH₃OH) = (2.76 mol CH + 9.20 mol) x( 0.43 atm) = 0.13 atm

Hence, the partial pressure rounded to two significant figures is 0.13 atm

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2 years ago

The balanced redox reactions for the sequential reduction of vanadium are given below.

Minchanka [31]

Answer : 0.0392 grams of Zn metal would be required to completely reduced the vanadium.

Explanation :

Let us rewrite the given equations again.

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