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adoni [48]
3 years ago
8

The behavior of real gases most closely resembles that of ideal gases under conditions of

Chemistry
1 answer:
blsea [12.9K]3 years ago
8 0
High temperature and low pressure. At high temperature, the kinetic energy of the gas particles increases and they move farther from each other. At low pressure, the gas particles are less likely to collide with each other. 
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A compound is found to contain 33.3%
kakasveta [241]

Answer: CaSO3

Explanation:Please see attachment for explanation

3 0
4 years ago
Calculate the osmotic pressure of a magnesium citrate laxative solution containing 25.5 g of magnesium citrate in 244 mL of solu
Vera_Pavlovna [14]

Answer:

The answer to your question is π = 12.47 atm

Explanation:

Data

mass of Magnesium citrate = 25.5 g

volume of solution = 244 ml

temperature = 37°C

molar mass C₆H₆MgO₇ = (12 x 6) + (1 x 6) + (24 x 1) + (16 x 7) = 214 g

Osmotic pressure = π = ?

Process

1.- Calculate the moles of magnesium citrate

                         214 grams ----------------- 1 mol

                          25.5 grams ---------------  x

                           x = (25.5 x 1)/214

                           x = 0.119

2.- Calculate molarity

Molarity = moles/volume

Molarity = 0.119/0.244

Molarity = 0.49

3.- Calculate osmotic pressure

π = MRT

π = (0.49)(0.0821)(37 + 273)

π = (0.49)(0.0821)(310)

π = 12.47 atm

7 0
3 years ago
Gold’s natural state has a definite shape and a definite volume. What is gold’s natural state(s)?
Mekhanik [1.2K]

Answer:

Solid

Explanation:

6 0
3 years ago
Read 2 more answers
Place these ions in order of preferential discharge, 1-4,where 1 is the most and 4 is least perfered.
egoroff_w [7]

Answer:

Silver ions 1 Hydrogen ions 2 Iron ions 3 Sodium ions 4

Explanation:

6 0
3 years ago
Question 27
3241004551 [841]

Answer:

24.9mL of the stock solution are required

Explanation:

To solve this question we have to find, as first, the moles of HCl that we need to prepare the desire solution. These moles are taken from the stock solution as follows:

<em>Moles diluted solution:</em>

500.0mL = 0.5000L * (0.613mol / L) = 0.3065 moles HCl

As these moles comes from the 12.3M HCl solution, the volume that we need of the stock solution is:

<em>Volume stock solution:</em>

0.3065 moles HCl * (1L / 12.3moles) = 0.0249L 12.3M HCl =

<h3>24.9mL of the stock solution are required</h3>
3 0
3 years ago
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