If you have 600g of nitroglycerin, how many moles do you have?<br><br> help please

When pressure is increased on the following equilibrium, where will the shift be? 3H2 + N2 2NH3

ahrayia [7]

Answer:

Explanation:

it is based on le chatliers principles

the left side of reaction you have 4 moles , where as at the right hand side you have 2 moles,,,,

so when you increase the pressure the reaction will shift towards the lower moles producing reaction that is reaction move towards forward in you case.

4 0

3 years ago

How much of 500 grams of carbon-14 remains after 28,575 years?

ser-zykov [4K]

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7 0

3 years ago

Suppose of copper(II) acetate is dissolved in of a aqueous solution of sodium chromate. Calculate the final molarity of acetate

uranmaximum [27]

Answer:

0.0714 M for the given variables

Explanation:

The question is missing some data, but one of the original questions regarding this problem provides the following data:

Mass of copper(II) acetate: $m_{(AcO)_2Cu} = 0.972 g$

Volume of the sodium chromate solution: $V_{Na_2CrO_4} = 150.0 mL$

Molarity of the sodium chromate solution: $c_{Na_2CrO_4} = 0.0400 M$

Now, when copper(II) acetate reacts with sodium chromate, an insoluble copper(II) chromate is formed:

$(CH_3COO)_2Cu (aq) + Na_2CrO_4 (aq)\rightarrow 2 CH_3COONa (aq) + CuCrO_4 (s)$

Find moles of each reactant. or copper(II) acetate, divide its mass by the molar mass:

$n_{(AcO)_2Cu} = \frac{0.972 g}{181.63 g/mol} = 0.0053515 mol$

Moles of the sodium chromate solution would be found by multiplying its volume by molarity:

$n_{Na_2CrO_4} = 0.0400 M\cdot 0.1500 L = 0.00600 mol$

Find the limiting reactant. Notice that stoichiometry of this reaction is 1 : 1, so we can compare moles directly. Moles of copper(II) acetate are lower than moles of sodium chromate, so copper(II) acetate is our limiting reactant.

Write the net ionic equation for this reaction:

$Cu^{2+} (aq) + CrO_4^{2-} (aq)\rightarrow CuCrO_4 (s)$

Notice that acetate is the ion spectator. This means it doesn't react, its moles throughout reaction stay the same. We started with:

$n_{(AcO)_2Cu} = 0.0053515 mol$

According to stoichiometry, 1 unit of copper(II) acetate has 2 units of acetate, so moles of acetate are equal to:

$n_{AcO^-} = 2\cdot 0.0053515 mol = 0.010703 mol$

The total volume of this solution doesn't change, so dividing moles of acetate by this volume will yield the molarity of acetate:

$c_{AcO^-} = \frac{0.010703 mol}{0.1500 L} = 0.0714 M$

8 0

4 years ago

Is it a spontaneous or non-spontaneous change?

joja [24]

Spontaneous is no spontaneous

7 0

3 years ago

How do you predict a reaction outcome for Ni(s) + H2O(L)?

ElenaW [278]

Answer:

Ni(s) + H₂O(l) -------------> [Ni(H₂O)₆]²⁺

Explanation:

Data Given:

Reactants:

Ni(s) + H₂O(l)

Product = ?

Solution:

Names of the Reactants

Ni = Nickel

H₂O = water

Reaction:

Normally nickel directly does not react with water under normal condition. But indirectly in acidic or neutral condition it form complex ion.

For this it first dissolve slowly in dilute acid, in this reaction it liberate Ni²⁺ ions these nickel ions form light green complex ions in aqueous solution.

Ni(s) + H₂SO₄(aq) -------> Ni²⁺(aq) + SO₄²⁻(aq) + H₂

This is a type of complex formation in which Nickel react with water and produced a light green color new complex ion or product.

Complete reaction is as under

Ni(s) + H₂O(l) -------------> [Ni(H₂O)₆]²⁺

Balance Reaction:

Ni(s) + 6 H₂O(l) -------------> [Ni(H₂O)₆]²⁺

So.

by this reaction one product is formed that is [Ni(H₂O)₆]²⁺ named as hexaqua nickel ion

7 0

3 years ago

If you have 600g of nitroglycerin, how many moles do you have? help please