Given: Please see the attached image below.
To be able to
subtract vectors, we can either use the parallelogram method or the triangle
method. Take note that the only difference is that alternatively adding vectors
A and B, we will instead be adding A and – B. When we ponder of vector subtraction, we must
anticipate about it in terms of adding a negative vector. A negative vector has the same magnitude as the
original vector, however, it has an opposite direction.
So in this problem, the two vectors that will have the
largest magnitude are A & F when subtracted (i.e., when one vector is
subtracted from the other).
Answer:
ΔU = 5.21 × 10^(10) J
Explanation:
We are given;
Mass of object; m = 1040 kg
To solve this, we will use the formula for potential energy which is;
U = -GMm/r
But we are told we want to move the object from the Earth's surface to an altitude four times the Earth's radius.
Thus;
ΔU = -GMm((1/r_f) - (1/r_i))
Where;
M is mass of earth = 5.98 × 10^(24) kg
r_f is final radius
r_i is initial radius
G is gravitational constant = 6.67 × 10^(-11) N.m²/kg²
Since, it's moving to altitude four times the Earth's radius, it means that;
r_i = R_e
r_f = R_e + 4R_e = 5R_e
Where R_e is radius of earth = 6371 × 10³ m
Thus;
ΔU = -6.67 × 10^(-11) × 5.98 × 10^(24)
× 1040((1/(5 × 6371 × 10³)) - (1/(6371 × 10³))
ΔU = 5.21 × 10^(10) J
By definition, we have that the gravitational force is given by:

Where,
G: gravitational constant
m1: mass of object number 1
m2: mass of object number 2
r: distance between both objects.
Therefore, for the gravitational force to increase, the following conditions must be met:
1) Increase the mass of the objects so that the numerator of the equation is greater.
2) Decrease the distance between the objects so that the denominator of the equation is smaller.
Answer:
A change that will always result in an increase in the gravitational force between two objects is:
increasing the masses of the objects and decreasing the distance between the objects
I believe the correct answer is true. Mechanical waves use matter to transfer energy. It <span> is a </span>wave<span> that is an oscillation of matter, and therefore transfers energy through a medium. Hope this answers the question. Have a nice day.</span>