Answer:
0.052 M
0.059 m
Explanation:
There is some missing info. I think this is the complete question.
<em>A student dissolves 4.6 g of glucose in 500 mL of a solvent with a density of 0.87 g/mL. The student notices that the volume of the solvent does not change when the glucose dissolves in it. Calculate the molarity and molality of the student's solution. Round both of your answers to 2 significant digits.</em>
Step 1: Calculate the moles of glucose (solute)
The molar mass of glucose is 180.16 g/mol.
4.6 g × 1 mol/180.16 g = 0.026 mol
Step 2: Calculate the molarity of the solution
0.026 moles of glucose are dissolved in 500 mL (0.500 L) of solution. We will use the definition of molarity.
M = moles of solute / liters of solution
M = 0.026 mol / 0.500 L = 0.052 M
Step 3: Calculate the mass corresponding to 500 mL of the solvent
The solvent has a density of 0.87 g/mL.
500 mL × 0.87 g/mL = 435 g = 0.44 kg
Step 4: Calculate the molality of the solution
We will use the definition of molality.
m = moles of solute / kilograms of solvent
m = 0.026 mol / 0.44 kg = 0.059 m
