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Mashcka [7]
2 years ago
11

Question 18 (5 points)

Chemistry
1 answer:
NeX [460]2 years ago
7 0

Answer:

d. oxygen is a pure substance and rocks are mixtures

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<span>N2 - Element; Pure substance O2 - Element; Pure substance N2O - Compound; Pure Substance Air - Homogeneous; Solution</span>
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What is the strongest type of intermolecular force between solve and solvent in Cu(s) in Ag(s)?
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The strongest intermolecular forces are in ion-ion bonds which happen when a metal bonds to another metal. 2. The next strongest forces are ion-dipole bonds which happen when metals bond to nonmetals. 3.

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In the Reaction CuCl2 + 2 NaNO3 —&gt; Cu(NO3)2 + 2 Naci
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The molar mass of the compounds are incorrect

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Positive feedback is when the change caused by the stimulus is A )decreased B) changes constantly C) nonexistent D) Increased HE
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3 years ago
Various members of a class of compounds, alkenes, react with hydrogen to produce a corresponding alkane. Termed hydrogenation, t
Vitek1552 [10]

<u>Answer:</u> The mass of decane produced is 1.743\times 10^2g

<u>Explanation:</u>

To calculate the number of moles, we use the equation:  

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}       ......(1)

Mass of hydrogen gas = 2.45 g

Molar mass of hydrogen gas = 2 g/mol

Putting values in equation 1:, we get:

\text{Moles of }H_2=\frac{2.45g}{2g/mol}=1.225mol

The chemical equation for the hydrogenation of decene follows:

C_{10}H_{20}(l)+H_2(g)\rightarrow C_{10}H_{22}(s)

As, decene is present in excess. So, it is considered as an excess reagent.

Thus, hydrogen gas is a limiting reagent because it limits the formation of products.

By Stoichiometry of the reaction:

1 mole of hydrogen gas produces 1 mole of decane.

So, 1.225 moles of hydrogen gas will produce = \frac{1}{1}\times 1.225=1.225mol of decane

Now, calculating the mass of decane by using equation 1, we get:

Moles of decane = 1.225 mol

Molar mass of decane = 142.30 g/mol

Putting values in equation 1, we get:

1.225mol=\frac{\text{Mass of decane}}{142.30g/mol}\\\\\text{Mass of carbon dioxide}=(1.225mol\times 142.30g/mol)=174.3g=1.743\times 10^2g

Hence, the mass of decane produced is 1.743\times 10^2g

5 0
3 years ago
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