Answer:
A skater glides along a circular path. She defines a certain point on the circle as her origin. Later on, she passes through a point at which the distance she has traveled along the path from the origin is smaller than the magnitude of her displacement vector from the origin.
So here in circular motion of the skater we can see that the total path length of the skater is along the arc of the circle while we can say that displacement is defined as the shortest distance between initial and final position of the object.
So it is not possible in any circle that arc-length is less than the chord joining the two points on the circle
As we know that arc length is given as
length of chord is given as
so here
so we have
Vf = 0 m/s
<span>t = 10 s </span>
<span>a = ? </span>
<span>a = Vf - Vi /t </span>
<span>a = -2m/s^2 </span>
<span>"a" is decelration
i hope this helps :)</span>
(a) 3000 V
For two parallel conducting plates, the potential difference between the plates is given by:
where
E is the magnitude of the electric field
d is the separation between the plates
Here we have:
is the electric field
d = 4.00 cm = 0.04 m is the distance between the plates
Substituting,
(b) 750 V
The potential difference between the two plates A and B is
Let's take plate A as the plate at 0 volts:
The potential increases linearly going from plate A (0 V) to plate B (3000 V).
So, if the potential difference between A and B, separated by 4 cm, is 3000 V, then the potential difference between A and a point located at 1 cm from A is given by the proportion:
and solving for V(1 cm) we find: