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3 years ago

15

2. A student drew the diagram below to model the movement of an object orbiting the Sun. Which object was she most likely modeli

ng? a meteor a planet a comet an astroid

1 answer:

Rufina [12.5K]3 years ago

3 0

Answer:

A comet

Explanation:

The picture is of an elliptical orbit of a comet. You can tell it is a comet because of the tail. Also, I just took the test and it was a comet.

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An electron in the first energy level of the electron cloud has an electron in the third energy level

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Brainliest if correct Question 1 of 10

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2 years ago

A basketball is tossed up at an initial speed of 20 m/s.

qwelly [4]

Gravity slows the upward speed of any rising object by 9.8 m/s every second.

If the ball is tossed upward at 20 m/s, then it's at the top of its arc and its speed has dwindled to zero in (20/9.8) = 2.04 seconds.

During that time, its starting speed is 20 m/s and its ending speed is zero, so its AVERAGE speed all the way up is (1/2) (20 + 0) = 10 m/s .

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2 years ago

In 0.601 s, a 13.1-kg block is pulled through a distance of 4.19 m on a frictionless horizontal surface, starting from rest. The

Naya [18.7K]

Answer:

0.615 m

Explanation:

We need to determine the force on the spring first. By Newton's second law of motion, force is the product of the mass and acceleration. The mass is given.

The acceleration is determined using the equation of motion.

Given parameters:

Initial velocity, <em>u</em> = 0.00 m/s

Distance, <em>s</em> = 4.19 m

Time, <em>t</em> = 0.601 s

We use the equation

$s = ut+\frac{1}{2}at^2$

With <em>u</em> = 0.00 m/s,

$s = \frac{1}{2}at^2$

$a = \dfrac{2s}{t^2}$

$a = \dfrac{2\times4.19\text{ m}}{(0.601\text{ s})^2} = 23.2\text{ m/s}^2$

The force is

$F = (13.1\text{ kg})(23.2\text{ m/s}^2) = 303.92 \text{ N}$

From Hooke's law, the extension, <em>e</em>, of a string is given by

$e = \dfrac{F}{k}$

where <em>k</em> is the spring constant.

Hence,

$e = \dfrac{303.92\text{ N}}{494\text{ N/m}} = 0.615\text{ m}$

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3 years ago