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antoniya [11.8K]
3 years ago
7

Plssss its a chem test help me

Chemistry
1 answer:
ad-work [718]3 years ago
6 0

Answer:

a. looks to be directly proportional because as one goes up, so does the other.

b. the pressure can be found from the line you create with the x and y values. the pressure will be less than 726 since you can see the values go down as temp goes down.

if that website calculator does not have an equation creator, you'd have to use excel to calculate pressure at 0°c, there's an excel function thst would estimate the value.

since it's a test, this was the fastest info I could gather.

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25 grams of glass by 5.oc aluminium iron glass copper water

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A low energy electromagnetic wave would also have?
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Atoms with different numbers of neutrons in their nucleus are:.
bonufazy [111]

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Why is it important to test the crucible for cracks before heating it?
solmaris [256]

It important to test the crucible for cracks before heating it because it can break while performing the chemical reaction.

The crucible and the lid should be inspected to check for the before heating it to prevent the breaking while performing the reactions. if there are some breaks in the crucible then if we heat the crucible it can lead to breaking of the whole crucible and the material  from the crucible to come out and it will come in contact with the lid.

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7 0
1 year ago
if you started with 2.34 grams of methane and 8.32 grams of oxeygyn and the combustion reaction went to completion how many gram
Romashka-Z-Leto [24]

Answer:

Mass of CO₂ produced  = 5.72 g

Explanation:

Given data:

Mass of methane = 2.34 g

Mass of oxygen = 8.32 g

Mass of CO₂ produced = ?

Solution:

Chemical equation:

CH₄ + 2O₂    →      CO₂ + 2H₂O

Number of moles of methane:

Number of moles = mass/molar mass

Number of moles =  2.34 g/ 16 g/mol

Number of moles = 0.146 mol

Number of moles of oxygen:

Number of moles = mass/molar mass

Number of moles =  8.32 g/ 32 g/mol

Number of moles = 0.26 mol

Now we will compare the moles of carbon dioxide with oxygen and methane.

                         CH₄             :              CO₂

                           1                 :              1

                        0.146            :           0.146

                         O₂                :               CO₂

                          2                 :                   1

                     0.26                :              1/2×0.26 = 0.13 mol

Less number of moles of CO₂ are produced by oxygen thus oxygen will react as limiting reactant.

Mass of CO₂:

Mass = number of moles × molar mass

Mass = 0.13 mol ×  44 g/mol

Mass = 5.72 g

4 0
3 years ago
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