An asteroid is not considered a moon because it is a rock that floats in space and sometimes gravity pulls it in a different direction.
In
this case, we can simply use a ruler to measure the heights of the signal. Use the
same ruler all throughout to reduce deviations in the measurement.
So
for example we have 3 isotopes, so we get 3 signals with heights of (for
example):
isotope
1 = 62
isotope
2 = 2
isotope
3 = 8
Therefore
the mass of the signals would be:
62
+ 2 + 8 = 72
The
fractional abundance of each isotope would be:
frac
isotope 1 = 62/72 = 0.86
frac
isotope 2 = 2/72 = 0.03
<span>frac
isotope 3 = 8/72 = 0.11</span>
Answer:
165.726 g.
Explanation:
- For the balanced equation:
<em>Cr₂O₃ + 3H₂S → Cr₂S₃ + 3H₂O,</em>
It is clear that 1 mol of Cr₂O₃ and 3 mol of H₂S to produce 1 mol of Cr₂S₃ and 3 mol of H₂O.
- Firstly, we need to calculate the no. of moles of 324.8 g of chromium(III) sulphide:
no. of moles of Cr₂S₃ = mass/molar mass = (324.8 g)/(200.19 g/mol) = 1.62 mol.
- Now, we can find the "no. of grams" of H₂S are needed:
<u><em>Using cross multiplication:</em></u>
3 mol of H₂S produces → 1 mol of Cr₂S₃, from stichiometry.
??? mol of H₂S produces → 1.62 mol of Cr₂S₃.
∴ The no. of moles of H₂S are needed = (3 mol)(1.62 mol)/(1 mol) = 4.86 mol.
∴ The "no. of grams" of H₂S are needed = (no. of moles of H₂S)(molar mass of H₂S) = (4.86 mol)(34.1 g/mol) = 165.726 g.