Answer: n=2,l=1,ml=1 n=3,l=2,ml=0 n=3,l=3,ml=2 n=4,l=2,ml=0.
Explanation:
hope it helps
Hydrogen peroxide is a powerful oxidizer. When exposed to sunlight it quickly decomposes to form water and oxygen as given by the following equation.
2H2O2(aq) → 2H2O(l) + O2(g)
Hydrogen peroxide is commercially available as a 30% w/w solution, which is the concentration that would facilitate the above reaction. This implies that the concentration would be 30 g of H2O2 in 100 g of the solution.
A material that allows heat/electricity to transfer is called a conductor.
<span>aluminium phosphide AlP</span>
<span>Answer:
A 0.04403 g sample of gas occupies 10.0-mL at 289.0 K and 1.10 atm. Upon further analysis, the compound is found to be 25.305% C and 74.695% Cl. What is the molecular formula of the compound?
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Seems like I did a problem very similar to this--this must be the "B" test. But the halogen was different.
25.305% C/12 = 2.108
74.695% Cl/35.5 = 2.104
So the empirical formula would be CH. However, there are many compounds which fit this bill, so we have to use the gas data. (And I made, in the previous problem, the simplifying assumption that 289C and 1.10 atm would offset each other, so I'll do that, too.)
0.044 grams/10 ml = x/22.4 liters
0.044g/0.010 liters = x/22.4 liters
22.4 liters/0.010 liters = 2240 (ratio)
2240 x .044 = 98.56 (actual atomic weight)
CCl = 35.5+12 or 47.5, so two of those is 95 grams/mole.
This is sufficiient to distinguish C2CL2, (dichloroacetylene)
from C6CL6 (hexachlorobenzene) which would
mass 3 times as much.</span>
