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Gekata [30.6K]
2 years ago
13

This for my previous question.. im so sorry

Physics
1 answer:
Marta_Voda [28]2 years ago
3 0

Answer:

the answer for the question is C

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A cruise ship made a trip to Guam and back. The trip there took 12 hours and the trip
Alecsey [184]

Answer:

The average speed is 8.0 km/h

Explanation:

We use the data for the return journey to calculate the distance travelled using the constant velocity equation:

s  =  v  t  =6*4=24km

 

Note I didn't change any units so the answer comes out in kilometres.

Now use the distance and time taken to travel to Guam to find the average speed:

v=st=24/3=8.0km/h

6 0
3 years ago
How can meteorologists use the jet stream to predict the weather ?
barxatty [35]
<span>Jet streams act as an invisible director of the atmosphere and are largely responsible for changes in the weather across the globe.
Hope this helps</span>
5 0
3 years ago
Hydrogen is in Group 1A of the periodic table, known as the alkali metals, although it obviously isn't a metal. What is the reas
jeka57 [31]
It's highly reactive and contains only one valence electron
6 0
3 years ago
What is a homopolar motor?????)
PSYCHO15rus [73]

Answer:

A homopolar motor is a direct current electric motor with two magnetic poles, the conductors of which always cut unidirectional lines of magnetic flux by rotating a conductor around a fixed axis so that the conductor is at right angles to a static magnetic field.

Explanation:

7 0
3 years ago
Read 2 more answers
To practice problem-solving strategy 22.1: gauss's law. an infinite cylindrical rod has a uniform volume charge density ρ (where
BabaBlast [244]

Let say the point is inside the cylinder

then as per Gauss' law we have

\int E.dA = \frac{q}{\epcilon_0}

here q = charge inside the gaussian surface.

Now if our point is inside the cylinder then we can say that gaussian surface has charge less than total charge.

we will calculate the charge first which is given as

q = \int \rho dV

q = \rho * \pi r^2 *L

now using the equation of Gauss law we will have

\int E.dA = \frac{\rho * \pi r^2* L}{\epcilon_0}

E. 2\pi r L = \frac{\rho * \pi r^2* L}{\epcilon_0}

now we will have

E = \frac{\rho r}{2 \epcilon_0}

Now if we have a situation that the point lies outside the cylinder

we will calculate the charge first which is given as it is now the total charge of the cylinder

q = \int \rho dV

q = \rho * \pi r_0^2 *L

now using the equation of Gauss law we will have

\int E.dA = \frac{\rho * \pi r_0^2* L}{\epcilon_0}

E. 2\pi r L = \frac{\rho * \pi r_0^2* L}{\epcilon_0}

now we will have

E = \frac{\rho r_0^2}{2 \epcilon_0 r}


7 0
3 years ago
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