<h3>
Answer:</h3>
209.236 kg · m/s
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Physics</u>
<u>Momentum</u>
Momentum Formula: P = mv
- P is momentum (in kg · m/s)
- m is mass (in kg)
- v is velocity (in m/s)
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
m₁ = 87.2 kg
v₁ = 2.87 m/s
m₂ = 0.0520 kg
v₂ = 789 m/s
<u>Step 2: Find Momentums</u>
<em>Football Player</em>
- Substitute [MF]: P = (87.2 kg)(2.87 m/s)
- Multiply: P = 250.264 kg · m/s
<em>Bullet</em>
- Substitute [MF]: P = (0.0520 kg)(789 m/s)
- Multiply: P = 41.028 kg · m/s
<u>Step 3: Find difference</u>
- Define equation: P₁ - P₂
- Substitute: 250.264 kg · m/s - 41.028 kg · m/s
- Subtract: 209.236 kg · m/s
Answer:
Explanation:
Given
charge of first body 
charge of second body 
Particle 1 is at origin and particle 2 is at 
third Particle which charge +q must be placed left of 
because it will repel the q charge while 
will attract it
suppose it is placed at a distance of x m
Solution:
initial sphere mvr = final sphere mvr + Iω
where I = mL²/3 = 2.3g * (2m)² / 3 = 3.07 kg·m²
0.25kg * (12.5 + 9.5)m/s * (4/5)2m = 3.07 kg·m² * ω
where: ω = 2.87 rad/s
So for the rod, initial E = KE = ½Iω² = ½ * 3.07kg·m² * (2.87rad/s)²
E = 12.64 J becomes PE = mgh, so
12.64 J = 2.3 kg * 9.8m/s² * h
h = 0.29 m
h = L(1 - cosΘ) → where here L is the distance to the CM
0.03m = 1m(1 - cosΘ) = 1m - 1m*cosΘ
Θ = arccos((1-0.29)/1) = 44.77 º
Answer:
C.) A high velocity and Large mass.
Explanation:
Momentum of any object is defined by following formula
Here
: m = mass of object
v = velocity of object
now we know that since momentum is product of mass and velocity
So in order to have more momentum we need the value of this product to be more. So this product will me large is both the physical quantity will be more in magnitude. So if mass is large and velocity will be more then the product of them will be large and hence the momentum of object will be more. Btw I had that question too.
Answer:
A Shunt is a passive element, usually resistive, that is used to bypass current around another element, like a meter, that is not able to handle the full current flow. ... A Multiplier is an active element that amplifies a voltage or current to enable a less sensitive device or circuit to make use of it.
